我将this Websocket library中的示例用于here,以基于websocket创建多个服务。
接受请求的主要服务器是Nginx服务器,该服务器根据请求的来源(基于域)转发请求,因此我可以确定接收到的请求是针对Websocket的。
问题出在这里
public void onOpen(WebSocket ws, ClientHandshake handshake) {
System.out.println("-------------------------------");
System.out.println(ws.getRemoteSocketAddress());
System.out.println("-------------------------------");
}
getRemoteSocketAddress 将始终返回nginx服务器IP,例如 /192.168.1.100:43556
我的nginx配置是:
server{
listen 80;
server_name we.mydomain.com;
access_log /var/log/nginx/access-ws-debug.log;
error_log /var/log/nginx/error-ws-debug.log;
set_real_ip_from 192.168.1.0/24;
real_ip_header X-Real-IP;
real_ip_recursive on;
location / {
proxy_pass http://192.168.1.101:54321;
proxy_http_version 1.1;
proxy_set_header X-Real-IP $remote_addr;
proxy_set_header Host $http_host; #host
proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for;
proxy_set_header Y-Real-IP $realip_remote_addr;
proxy_set_header Upgrade $http_upgrade;
proxy_set_header Connection "Upgrade";
proxy_connect_timeout 1d;
proxy_send_timeout 1d;
proxy_read_timeout 1d;
}
}
nxing配置是否有问题?还是有其他方法可以将用户的IP获取到websocket后面?
已解决,感谢Mark的回答。以下代码与提到的库无关。这是没有任何库的jsp中的“经典” Web实现。
我将握手修改为如下形式:
@Override
public void modifyHandshake(
ServerEndpointConfig config,
HandshakeRequest request,
HandshakeResponse response
) {
HttpSession httpSession = (HttpSession) request.getHttpSession();
config.getUserProperties().put(HttpSession.class.getName(), httpSession);
config.getUserProperties().put("Headers",request.getHeaders());
}
要获取标题,只需在OnOpen中调用它即可
@OnOpen
public void onOpen(final Session session, EndpointConfig config){ //This happens when javascript opens socket session
Object list = config.getUserProperties().get("Headers");
System.out.println("-------------------------------------");
System.out.println(list);
System.out.println("-------------------------------------");
}
标题的返回格式如下(使用我的手机)
{upgrade=[websocket],
accept-language=[en-US,en;q=0.9,es;q=0.8],
cookie=[JSESSIONID=0BAE99DFDE5DD81D20CFF04E4257D7FE],
sec-websocket-extensions=[permessage-deflate; client_max_window_bits],
origin=[https://mywebsite.com],
x-forwarded-for=[1.2.3.4],
sec-websocket-version=[13],
pragma=[no-cache],
x-real-ip=[1.2.3.4],
y-real-ip=[1.2.3.4],
host=[mywebsite.com],
connection=[Upgrade],
sec-websocket-key=[ZroOewrBGrg660x7ocI+nog==],
cache-control=[no-cache],
accept-encoding=[gzip, deflate, br],
user-agent=[Mozilla/5.0 (Linux; Android 8.0.0; SM-N950F) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.80 Mobile Safari/537.36]}
该IP在我所在的地区可以进行地理位置定位。
答案 0 :(得分:2)
这不是一件容易的事,但是您的配置看起来不错,您只需要从设置的标头(X-Real-IP
中获得原始IP。
import javax.websocket.*;
import javax.websocket.server.HandshakeRequest;
import javax.websocket.server.ServerEndpoint;
import javax.websocket.server.ServerEndpointConfig;
@ServerEndpoint(value = "/test", configurator = Test.TestConfiguratior.class)
public class Test extends Endpoint {
@Override
public void onOpen(Session session, EndpointConfig endpointConfig) {
Object o = endpointConfig.getUserProperties().get(TestConfiguratior.HEADER_NAME);
//o should be the string object you are looking for
}
@OnMessage
public void onMessage(Session session, String msg) {
//do what u want
}
public static class TestConfiguratior extends ServerEndpointConfig.Configurator {
static String HEADER_NAME = "X-Real-IP";
@Override
public void modifyHandshake(ServerEndpointConfig sec, HandshakeRequest request, HandshakeResponse response) {
String firstFoundHeader = request.getHeaders().get(HEADER_NAME.toLowerCase()).get(0);
sec.getUserProperties().put(HEADER_NAME, firstFoundHeader);
}
}
}
TL.DR .:您可以使用javax.websocket.EndpointConfig#getUserProperties
映射将数据放入其中并在以后检索。最初,我认为这可能会在使用此确切代码时引起一些并发问题,但是我无法重现它。甚至文档也建议这样做:
https://javaee.github.io/tutorial/websocket010.html
更新: :这是一个JSR 356
示例,并不专门针对上述框架。