Question

首先，任何不包含纬度和经度的对象都将被过滤掉。我将输入一个包含以下输入的JSON的URL。然后，我想解析该JSON数据，并使用该数据以[纬度，经度，位置]格式将以下内容作为JSON数组输出。我该怎么做？（注意：字符串中的纬度和经度需要转换为浮点数）

import json
import urllib.request

def getData(url):
    dictionary = {}
    response = urllib.request.urlopen(url)
    content = response.read().decode()
    response1 = json.loads(content)
    for i in response1:
        for element in i:
            if element == 'longitude' and element == 'latitude':
                float(i['longitude'])
                float(i['latitude'])
                dictionary.update(i)
    total = [[_.get("latitude"), _.get("longitude"), _.get("location")] for _ in dictionary]
    return json.dumps(total)

输入：

[{"capital": "Yes", "latitude": "35.6895", "longitude": "139.6917", "location": "Tokyo"}, 
{"capital": "Yes","latitude": "39.9042", "longitude": "116.4074", "location": "Beijing"}, 
{"capital": "No", "location": "Shanghai"}, {"capital": "No", "location": 
"Osaka"}]

预期输出：

"[[35.6895, 139.6917, "Tokyo"], [39.9042, 116.4074, "Beijing"]]"

Answer 1

使用列表理解

例如：

import json


response = [{"capital": "Yes", "latitude": "35.6895", "longitude": "139.6917", "location": "Tokyo"}, 
{"capital": "Yes","latitude": "39.9042", "longitude": "116.4074", "location": "Beijing"}, 
{"capital": "No", "location": "Shanghai"}, {"capital": "No", "location": 
"Osaka"}]

lst = [[float(i["latitude"]), float(i["longitude"]), i["location"] ] for i in response if ("latitude" in i) and ('longitude' in i)]
print(json.dumps(lst))

输出：

[[35.6895, 139.6917, "Tokyo"], [39.9042, 116.4074, "Beijing"]]

如何使用JSON数据输出格式化的嵌套数组？

1 个答案: