Question

我想使a1 = 0，a2 = 0，... aN = 0。我以为使用“用于”

例如N = 10

required

但它不是零（仅打印）。因此，我做了'a％d'％i = 0。但这没用

我该怎么做？

Answer 1

您可以为此使用字典。

var_name = 'a'

for i in range(0, 10):   
    key = var_name + str(i) # an
    new_values[key] = 0 # assign 0 to the new name

要单独访问它们，

new_values['a1']
>>> 0

或者您可以像这样一起访问它们，

for k,v in new_values.items():
    print(k,'=',v)

输出：

a0 = 0
a1 = 0
a2 = 0
a3 = 0
a4 = 0
a5 = 0
a6 = 0
a7 = 0
a8 = 0
a9 = 0

Answer 2

使用const值x=0和计数器i的简单解决方案：

x = 0
for i in range(0,10):
    print(f"a{i} = {x}")

输出：

a0 = 0
a1 = 0
a2 = 0
a3 = 0
a4 = 0
a5 = 0
a6 = 0
a7 = 0
a8 = 0
a9 = 0

Answer 3

对于打印，请使用.format() (or f-strings on python 3.6+：

for i in range(0, 10):
    print('a{} = {}'.format(i,i))  # the 1st i is put into the 1. {}, the 2nd i is put ...

如果要使用这些作为名称进行计算，请将它们存储在dictionary中，并使用值进行计算：

d = {}
for i in range(0, 10):
    d["a{}".format(i)] = i # the nth i is put instead nth {}

print("sum a4 to a7:  {} + {} + {} + {} = {}".format(   # use the values stored in dict to 
    d["a4"], ["a5"], ["a6"], ["a7"],                    # calculate and print the single 
    d["a4"]+d["a5"]+d["a6"]+d["a7"]))                   # values where needed

输出：

# for loop 
a0 = 0
a1 = 1
a2 = 2
a3 = 3
a4 = 4
a5 = 5
a6 = 6
a7 = 7
a8 = 8
a9 = 9

# calculation
sum a4 to a7:  4 + ['a5'] + ['a6'] + ['a7'] = 22

Answer 4

您还可以使用globals和locals内置函数。

In [1269]: for i in range(0, 10):
      ...:     globals()['a'+ str(i)] = 0
      ...:     

In [1270]: a1
Out[1270]: 0

In [1271]: a2
Out[1271]: 0

In [1272]: a3
Out[1272]: 0

In [1273]: a4
Out[1273]: 0

In [1274]: a5
Out[1274]: 0

In [1275]: a6
Out[1275]: 0

In [1276]: a7
Out[1276]: 0

In [1277]: a8
Out[1277]: 0

In [1278]: a9
Out[1278]: 0

我想使a1 = 0，a2 = 0 .. aN = 0

4 个答案: