Question

我需要接受用户输入，并让程序通过所有方法和东西来运行它，以输出最大和最小的数字。我可以打印最大的它，但是它总是最小的为0。这可能很容易修复，但这是本季度末，我强调要完成最后一个。这是我的代码。

import java.io.*;
import java.util.*;

public class P4_6
{
  private int sum;
  private int count;
  private int largest = Integer.MIN_VALUE;
  private int smallest = Integer.MAX_VALUE;

  public P4_6()
  {
    sum = 0;
    largest = 0;
    smallest = 0;
    count = 0;
  }
  public void addValue(int x)
  {
    smallest = Math.min(smallest, x);
    largest = Math.max(largest, x);
    sum = sum + x;
    count++;
  }

  public int getSum()
  {
    return sum;
  }

  public int getLargest()
  {

    return largest;
  }

  public int getSmallest()
  {
    return smallest;
  }

  public static void main(String[] args)
  {
    Scanner kbreader = new Scanner(System.in);
    System.out.println("Enter your first integer: ");
    int num1 = kbreader.nextInt();
    System.out.println("Enter your second integer: ");
    int num2 = kbreader.nextInt();
    System.out.println("Enter your third integer: ");
    int num3 = kbreader.nextInt();
    System.out.println("Enter your fourth integer: ");
    int num4 = kbreader.nextInt();

    P4_6 data = new P4_6();
    data.addValue(num1);
    data.addValue(num2);
    data.addValue(num3);
    data.addValue(num4);

    System.out.println("The largest was " + data.getLargest());
    System.out.println("The smallest was " + data.getSmallest());

  }
}

Answer 1

您不需要使用无参数构造函数。 Java编译器默认添加No-argument构造函数。您可以删除以下部分。

public P4_6()
{
 sum = 0;
 largest = 0;
 smallest = 0;
 count = 0;
}

如果您希望将此部分保留在代码中，则应按如下所示初始化变量

public P4_6()
{
 sum = 0;
 largest = Integer.MIN_VALUE;
 smallest = Integer.MAX_VALUE;
 count = 0;
}

Answer 2

您不需要初始化“最小”和“最大”。只需删除它们

public Test()
    {
        sum = 0;
        //largest = 0;
        //smallest = 0;
        count = 0;
    }

用java

2 个答案: