Question

我是Python的初学者。

我正在检索数据并将其保存到字典中。当第二次循环时，它将替换我的第一个键值。

您可以找到第二个Atfer match_chlDict的输出，将键"1"的值替换为键"2"。

我自己没有办法解决，请帮助。谢谢。

这是match_details ['chl']中的原始照片

[{'LINENUM': '1', 'LINESTATUS': '0', 'LINEORDER': '1', 'LINE': '9.5', 'H': '100@1.75', 'L': '100@1.95'}, {'LINENUM': '2', 'LINESTATUS': '1', 'LINEORDER': '2', 'LINE': '10.5', 'H': '100@2.20', 'L': '100@1.59'}]

代码

    match_chl={}
    match_chlDict={}
    for chl in match_details['chl']:          
        print("Current match_chlDict") 
        print(match_chlDict)
        match_chl['chlLINE']=chl['LINE']
        match_chl['chlH']=replace100(chl['H'])
        match_chl['chlL']=replace100(chl['L']) 
        #Write match_chl to dict by "LINENUM" as key                   
        match_chlDict[chl['LINENUM']]=match_chl    
        print("Atfer match_chlDict") 
        print(chl['LINENUM'])
        print(match_chlDict)

输出

Curr match_chlDict
{}

获得match_chlDict

1
{'1': {'chlLINE': '9.5', 'chlH': '1.75', 'chlL': '1.95'}}

Curr match_chlDict

{'1': {'chlLINE': '9.5', 'chlH': '1.75', 'chlL': '1.95'}}

获得match_chlDict

2
{'1': {'chlLINE': '10.5', 'chlH': '2.20', 'chlL': '1.59'}, '2': {'chlLINE': '10.5', 'chlH': '2.20', 'chlL': '1.59'}}

Answer 1

每次循环时都match_chl={}重新初始化，否则它将替换字典中的引用。

match_chl = {}
match_chlDict = {}
for chl in m:
    print("Current match_chlDict")
    print(match_chlDict)
    match_chl['chlLINE'] = chl['LINE']
    match_chl['chlH'] = 'a'
    match_chl['chlL'] = 'b'
    match_chlDict[chl['LINENUM']] = match_chl
    print("Atfer match_chlDict")
    print(chl['LINENUM'])
    print(match_chlDict)
    match_chl = {}

希望这会有所帮助！

Answer 2

def replace100(str):
    return(str.replace("100@",""))

for chl in data:
    match_chl = {}
    match_chl['chlLINE'] = chl['LINE']
    match_chl['chlH'] = replace100(chl['H'])
    match_chl['chlL'] = replace100(chl['L'])
    match_chlDict[chl['LINENUM']] = match_chl
match_chlDict

我不确定您要寻找什么，但是如果您想将第一个元素用作键，我想上面的代码可以工作。我认为您的错误可能是您将值存储在相同的match_chl中。您应该在每次循环开始时重置其值。

为什么dict设置相同的atfer循环

2 个答案: