Question

代码不执行任何操作

include 'connection.php';

$user = $_POST['user'];
$pass = $_POST['pass'];
$verify = "SELECT * FROM  `contas` WHERE  `user` =  'Richard'";
$create = "INSERT INTO  `tibitos`.`contas` (`pass` ,`user`) VALUES ('$pass',  '$user');";
if($con->query($verify)){
    echo mysqli_num_rows($verify);
}else{
    echo die($con->error);
}

?>

我正在尝试使代码显示“理查德”（Richard）中存在的列数，虽然有，但php不显示任何内容

我的代码有什么错误？请帮助我

如果我做错了什么，请纠正我

Answer 1

假设您建立了

$con= new mysqli("localhost", "my_user", "my_password", "my_table");

在connection.php

中

<?php

include 'connection.php';

$user = $_POST['user'];
$pass = $_POST['pass'];

$verify = "SELECT * FROM  `contas` WHERE  `user` =  'Richard'";
$create = "INSERT INTO  `tibitos`.`contas` (`pass` ,`user`) VALUES ('$pass',  '$user');";

// query returns mysqli result and not false
if( $result = $con->query($verify) ){

    // Assign and print out Numbers of row(s)
    echo $count = $result->num_rows;

    // Check your count and do ...
    if( $count == 0 ) {

        // insert values or whatever
        $result = $con->query($create);

    } else {}

} else {

    // on error
    exit();

}

?>

我无法检查列中是否存在该值

1 个答案: