Firebase云功能的图像调整大小性能问题

Question

我正在将Firebase与我的React项目一起使用，并在用户上传图片时尝试调整其大小。我正在使用的云功能可以正常工作，但是执行它需要花费8到10秒钟以上的时间，我觉得它不应该花那么长时间。我正在使用sharp库调整图像大小，并使用Firebase的“ Spark”（免费）计划。关于如何提高性能的任何想法？这是我的云函数：

const functions = require('firebase-functions');
const {Storage} = require('@google-cloud/storage');
const sharp = require('sharp');
const os = require('os');
const path = require('path');

const projectId = 'my-project-id';

const storage = new Storage({
    projectId: projectId
});

exports.resizeImage = functions.storage.object('images').onFinalize(event => {
    const {bucket, name, contentType, resourceState} = event;

    if (!contentType.startsWith('image/') || resourceState == 'not_exists') {
        console.log('This is not an image.');
        return {};
    }
    if (path.basename(name).startsWith('resized_')){
        console.log('Image already processed');
        return {};
    }

    const destinationBucket = storage.bucket(bucket);
    const workingDir = path.join(os.tmpdir());
    const tempFilePath = path.join(workingDir, path.basename(name));
    const metadata = {contentType: contentType};

    return destinationBucket.file(name).download({
        destination: tempFilePath
    })
    .then(() => {
        const newFilePath = path.join(workingDir, 'resized_' + path.basename(name));
        sharp(tempFilePath)
        .resize({width: 600})
        .toFile(newFilePath)
        .then( () => {
            return destinationBucket.upload(newFilePath, {destination: 'images/resized_' + path.basename(name)});
        })
        .catch( err => console.log(err))
    })
})