PHP中的POST,GET和Bootstrap模式

时间:2018-11-06 08:15:43

标签: php post get bootstrap-modal

页面“ A”包含以下形式:

在PageA.php中:

<form class="form-sign" method="post" id='s' name="s" action="pageB.php" 
    <div class="form-group">
        <p> Have a Discount code ? </p>
        <input class="form-control" type="text" name="codeact" id="codeact" value=""  placeholder=" Enter your code" required />
        <span class="help-block"></span>
    </div>
    <br>
    <a href="#test" data-toggle="modal">
        <button class="btn btn-primary btn-block" name = "submit" type="submit"> Start </button>
    </a>
</form>

如果输入的激活码正确,则会显示模态以指示计时器将启动。 通过在Modal中单击“确定”,将显示pageB.php。 我的模态:

div id="test" class="modal fade" role="dialog">
    <div class="modal-dialog modal-md">
        <div class="modal-content">
            <div class="modal-header">
                <h4 class="modal-title">Notice</h4>
            </div>
            <div class="modal-body">
                <div class="alert alert-danger">The timed test will now begin.
                </div>
                <div class="modal-footer">
                    <a href="pageB.php">
                        <button type="button" class="btn btn-danger">YES </button>
                    </a>
                    <button type="button" class="btn btn-default" data-dismiss="modal">No</button>
                </div>
            </div>
        </div>
    </div>
</div>

验证码:

$email = $_SESSION['email'];
$codeact = $_POST['codeact']; 
$query = "SELECT codeactivation FROM user where email ='".$email."'";
$result = mysqli_query($conn, $query);
while ($row = mysqli_fetch_array($result)) { 
    $codeactivation=$row['codeactivation'];
}
if($codeactivation==$codeact)
{}

1-如果代码正确,如何显示我的模态?否则,模态将不会显示。 2. pageB.php如何从pageA.php获取变量?

0 个答案:

没有答案