这是我尝试过的代码,
var array=[];
var list = this.state.list;
var getList = function(i){
var add = +i + 1;
return {
["value"+add]:{
Description:list[i].Description,
Length:list[i].Length,
Height:list[i].Height,
Weight:list[i].Weight,
VolumeWeight:list[i].VolumeWeight,
ActualWeight:list[i].ActualWeight,
}
}
}.bind(this)
for(var i in list){
array.push(getList(i));
}
var dataArray = array.map(function(e){
return JSON.stringify(e);
});
dataString = dataArray.join(",");
data1 = {
ConsigneeBranchName:this.state.searchText,
ConsigneeBranchCode:this.state.code,
ConsigneeBranchFullAddress:this.state.DAddress,
SenderBranchCode:this.state.code1,
SenderBranchName:this.state.searchTexts,
SenderBranchFullAddress:this.state.Address,
CreatedByEmployeeCode:id,
CreatedByEmployeeFullName:userName,
jsonString:{
JsonValues:{
id:"MyID",
values:dataString
}
}
}
但是我希望结果就是这样
var result = {
"ConsigneeBranchName":"",
"ConsigneeBranchCode":"",
"ConsigneeBranchFullAddress":"",
"SenderBranchCode":"",
"SenderBranchName":"",
"SenderBranchFullAddress":"",
"CreatedByEmployeeCode":"",
"CreatedByEmployeeFullName":"",
"jsonString":"{
"JsonValues": {
"id": "MyID",
"values": {
"value1":{
"Description”:"testSmarter1",
"Length”:"60",
"Height”:"50",
"Weight”:"70",
"VolumeWeight”:"75",
"ActualWeight”:”78"
},
"value2:{
"Description":"Documents",
"Length":"120",
"Height":"68",
"Weight":"75",
"VolumeWeight":"122.4",
"ActualWeight":"123"
},
}
}
}
};
请任何人帮助我
我希望在单个对象{key1:{des:1,value:as},key2:{des:2,value:aw},key3:{des:3,value:au}内具有动态键的对象}
请问我已经尝试了很多次了
请参见下面的图片我想要这部分,在单个对象内,我可以使用动态键来连接多个对象
答案 0 :(得分:0)
lodash已经具有一个名为 keyBy 的功能,您可以使用它来获得此功能。如果添加lodash在您的项目中没有意义。
我已经实现了香草JS版本。
function keyBy(array, mapperFn) {
const resultObj = {};
array.map(item => resultObj[mapperFn(item)] = item);
return resultObj;
}
function arrayToObject (array, keyName = 'id') {
return keyBy(array, function(element) {return element[keyName]});
}
API:
arrayToObject(targetArray, stringNameOfThePorpertyYouWantToUseAsKey);
用法:
const listOfUsers = [{name: 'Jenitha', reputation: 6}, {name: 'Chandan', reputation: 3}];
const mapOfUsersByName = arrayToObject(listOfUsers, 'name');