我目前正在学习php，我需要将产品ID（自动递增）存储到cookie中，然后检索该cookie并在更新页面上显示给用户。我知道Cookie不适用于存储表单数据，但这是出于教育目的。我提供了表单和验证代码的副本，然后调用了一个名为storefile2的文件以将详细信息发送到数据库并在更新页面上显示给用户。我在这个问题上陷入困境，将不胜感激。谢谢
$prodID = 0;
if (isset($_COOKIE['$prodID'])) {
$prodID = ++$_COOKIE['$prodID'];
}
else {
$productID = 1;
}
setcookie("'$prodID'", $prodID, time()+ (86400 * 365));
?>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Assessment 4</title>
<link rel="stylesheet" type="text/css" href="css/lever.css">
</head>
<style>
.error { color: #FF0000; }
.container {width:700px;margin:0 auto;}
.center {text-align:center;}
</style>
<body>
<?php
$errMessageName ="required field";
$errMessageFinish="required field";
$errMessageUsage = "required field";
$errMessageCost="required field";
$errMessageImage="required field";
$prodName="";
$prodFinish="";
$prodUsage="";
$prodCost="";
$prodID="";
$invalidData = false;
if ($_SERVER["REQUEST_METHOD"] == "POST") {
if(isset($_POST["reset"])){
header("Refresh:0");
exit();
}
//validate fields
$prodName = checkinput($_POST["Name"]);
$prodFinish = checkinput($_POST["Finish"]);
$prodUsage = checkinput($_POST["Usage"]);
$prodCost = checkinput($_POST["Cost"]);
$fileupload = $_FILES['userfile']['name'];
$filetype = $_FILES['userfile']['type'];
$filesize = $_FILES['userfile']['size'];
$tempname = $_FILES['userfile']['tmp_name'];
$filelocation = "images/$fileupload";
if($prodName == "") {
$errMessageName = "Product name must not be blank";
$invalidData = true;
}
elseif ($prodFinish == "") {
$errMessageFinish = "Product finish must not be blank";
$invalidData = true;
}
elseif ($prodUsage == ""){
$errMessageUsage = "Product Usage must not be blank";
$invalidData = true;
}
elseif (!filter_var($prodCost, FILTER_VALIDATE_FLOAT)) {
$errMessageCost = "Please enter a number only in decimal format eg: 1.00";
$invalidData = true;
}
//make sure a file has been entered
elseif($fileupload == "") {
$errMessageImage = "Please enter an image";
$invalidData = true;
}
//check file type
elseif (($_FILES['userfile']['type'] != "image/jpg") && ($_FILES['userfile']['type'] != "image/png")
&& ($_FILES['userfile']['type'] != "image/jpeg"))
{
$errMessageImage = "Only JPG & PNG files are allowed.";
$invalidData = true;
}
elseif (!move_uploaded_file($tempname,$filelocation)) {
switch ($_FILES['userfile']['error'])
{
case UPLOAD_ERR_INI_SIZE:
echo "<p>Error: File exceeds the maximum size limit set by the server</p>" ;
break;
case UPLOAD_ERR_FORM_SIZE:
echo "<p>Error: File exceeds the maximum size limit set by the browser</p>" ;
break;
case UPLOAD_ERR_NO_FILE:
echo "<p>Error: No file uploaded</p>" ;
break;
default:
echo "<p>File could not be uploaded </p>" ;
}
}
else
{
$conn = mysqli_connect("localhost:3306","root","");
// Check connection
if (mysqli_connect_errno())
{
echo "<p>Failed to connect to MySQL: " . mysqli_connect_error() . "</p>";
}
}
if ($invalidData == false) {
include('storefile2.php');
//Show thank you page
//header('Location: update.php');
exit();
}
}
function checkInput($inputData) {
$inputData = trim($inputData);
$inputData = stripslashes($inputData);
$inputData = htmlspecialchars($inputData);
return $inputData;
}
?>
<div class="container">
<h1>Acme Hardware</h1>
<h2>Door Levers - Product Entry Form</h2>
<h3>Enter the Door Lever Product Details into the form and and click the Submit button</h3>
<p>NOTE: * denotes required entry</p></br>
<form id="Form1" name="Form" method="post" enctype='multipart/form-data' action=<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>>
<label for="Name">Product Name: </label><input type="text" name="Name" id="Name" size="20" value="<?php echo
$prodName;?>"><span class="error">* <?php echo $errMessageName;?></span><br /><br />
<label for="Finish">Product Finish: </label> <input type="text" name="Finish" id="Finish" size="20" value="<?php echo
$prodFinish;?>"><span class="error">* <?php echo $errMessageFinish;?></span><br /><br />
<label for="Usage">Product Usage: </label><input type="text" name="Usage" id="Usage" size="20" value="<?php echo
$prodUsage;?>"><span class="error">* <?php echo $errMessageUsage;?></span><br /><br />
<label for="Cost">Product Cost: </label><input type="text" name="Cost" id="Cost" size="20" value="<?php echo
$prodCost;?>"><span class="error">* <?php echo $errMessageCost;?></span><br /><br />
<a href="ProductCost.php">Update product cost</a> <br/><br/>
<a href="deleteProduct.php">Delete product</a> <br/><br/>
<input type='hidden' name='MAX_FILE_SIZE' value='4000000'/>
<label for="userfile">Product image: </label><input type='file' id='userfile' name='userfile'><span class="error">* <?php echo $errMessageImage;?></span></br>
<input type="submit" name="submit" value="Submit"/>
<input type ="reset" name="reset" value ="Reset" title="Reset Form"/>
</form>
</div>
答案 0 :(得分：1)
如果您希望cookie名称中包含一个文字$字符，则在调用setcookie()时只需在名称周围使用单引号即可。
setcookie('$prodID', $prodID, time()+ (86400 * 365));
通过在双引号周围加上双引号，可以扩展该变量，因为双引号内的单引号没有特殊含义，因此它们被视为文字字符。
请参见What is the difference between single-quoted and double-quoted strings in PHP?
答案 1 :(得分：-1)
很抱歉，我真的没有时间尝试调试您的源代码，但是请先使用浏览器的浏览器调试功能来观察您之间的实际交互PHP代码（无论是什么）和实际的浏览器。
“设置Cookie”时，会发生 HTTP标头添加到将发送到客户端的下一个数据包中，并指定cookie的名称和值这是要采取的。客户端收到并处理了该标头后，它将在 HTTP标头中包含该cookie及其值，然后将其发送给主机... 。 “ 下一个时间。”
所以–使用浏览器检查那些标题。 是否主机实际上发送了设置cookie请求？此后客户端发送 吗？ （而且，如果可以，为什么您的服务器端代码看不到它？）