Question

我需要以下代码的帮助。我看不到这是如何从该地址行文本中提取数字的。当它（模式）说s/\D/ /时，我认为这会用空格替换数字。我知道这里的第二部分是将子字符串带到地址行文本中的第一个空格。但是，然后我看不到它是如何提取数字的。我拉起数据集，看起来确实可行。请帮助我了解它是如何工作的。

DATA OUT.REQ_1_2_03;
        SET OUT.REQ_1_2_02;
    /*  GET STREET NUMBER*/
        PRE_RCV_ST_NB=PRXCHANGE('s/\D/ /',-1,SUBSTR(PRE_RCV_ADDRESSS_LINE_1,1,PRXMATCH('/\s/',PRE_RCV_ADDRESSS_LINE_1)));
        POST_RCV_ST_NB=PRXCHANGE('s/\D/ /',-1,SUBSTR(POST_RCV_ADDRESSS_LINE_1,1,PRXMATCH('/\s/',POST_RCV_ADDRESSS_LINE_1)));
        PRE_HOST_ST_NB=PRXCHANGE('s/\D/ /',-1,SUBSTR(PRE_HOST_ADDR_LINE_1,1,PRXMATCH('/\s/',PRE_HOST_ADDR_LINE_1)));
        POST_HOST_ST_NB=PRXCHANGE('s/\D/ /',-1,SUBSTR(POST_HOST_ADDR_LINE_1,1,PRXMATCH('/\s/',POST_HOST_ADDR_LINE_1)));   
    RUN;

Answer 1

尝试通过示例来了解

     PRE_RCV_ADDRESSS_LINE_1 ="123hello Village st"

从代码左侧开始。

first use prxmatch and it finds first space(\s)that comes 123hello
do  substr till that space and you get 123hello
then remove  prxchanges to replace \D (that is anything other than digit) and 
is converted to 123

通过示例进行总结

 "123hello Village st" -- find space(\s) by prxmatch and substring till space gives "123hello"
 "123hello" is changed to "123" by prxchange which replaces anything other than digit(\D) .

 /* run this step to understand it better*/
 data want ;
 PRE_RCV_ADDRESSS_LINE_1 = "123hello Village st";
 test1= SUBSTR(PRE_RCV_ADDRESSS_LINE_1,1,PRXMATCH('/\s/',PRE_RCV_ADDRESSS_LINE_1));
 PRE_RCV_ST_NB= PRXCHANGE('s/\D//',-1,SUBSTR(PRE_RCV_ADDRESSS_LINE_1,1,PRXMATCH('/\s/',PRE_RCV_ADDRESSS_LINE_1)));
 run;

sas，regex，数字，子字符串，prxchange

1 个答案: