我尝试实现与tutorial稍有不同的示例:
object Test extends App {
class A extends Actor {
override def receive: Receive = {
case 10 => context.system.terminate()
case x =>
println(s"Received: $x")
sender() ! x
}
}
implicit val system = ActorSystem()
implicit val materializer = ActorMaterializer()
implicit val dispatcher = system.dispatcher
implicit val askTimeout = Timeout(1, TimeUnit.SECONDS)
val a = system.actorOf(Props[A])
val graph = RunnableGraph.fromGraph(GraphDSL.create() {
{
implicit builder: GraphDSL.Builder[NotUsed] => {
import GraphDSL.Implicits._
val source: Source[Int, NotUsed] = Source(1 to 10)
source ~> Flow[Int].ask(2)(a) ~> Sink.foreach[String](println)
ClosedShape
}
}
})
val x = graph.run()
}
结果我得到了:
已收到:1
已收到:2
但是我希望这样:
已收到:1
1
已收到:2
2
...
已收到:9
9
如果我通过Source.actorRef
向演员发送消息,则一切正常,演员接收到所有消息。似乎物化演员正在等待引用演员的响应。
如何解决?
答案 0 :(得分:2)
如果您将Sink.foreach[String](println)
替换为Sink.onComplete(println)
您会看到流终止并显示错误:
Received: 1
Received: 2
Failure(java.lang.ClassCastException: Cannot cast java.lang.Integer to scala.runtime.Nothing$)
问题在于Source.ask需要知道将演员的回复映射到see API docs的类。否则,它将尝试将回复投射为Nothing并在内部引发异常。
要修复您的原始代码,请用Ask [Int]替换ask:
val graph = RunnableGraph.fromGraph(GraphDSL.create() {
{
implicit builder: GraphDSL.Builder[NotUsed] => {
import GraphDSL.Implicits._
val source: Source[Int, NotUsed] = Source(1 to 10)
source ~> Flow[Int].ask[Int](2)(a) ~> Sink.foreach(println)
ClosedShape
}
}
})