假设我正在选择候选人的详细信息及其工作经历。
Select candidate.id, candidate.firstname +' '+ candidate.lastname as 'Candidate Name', cwh.dateworked
from candidate
inner join canworkhistory cwh on candidate.id = cwh.candidateid
现在,候选人的工作日期有很多记录,但是我只想要最新的记录。
如何排序这些子项,以便在上面的查询中返回前1个?
答案 0 :(得分:2)
您可以在外部应用最新行:
Select candidate.id, candidate.firstname +' '+ candidate.lastname as 'Candidate Name', cwh.dateworked
outer apply (select top 1 * from canworkhistory where candidate.id = canworkhistory.candidateid order by dateworked desc) cwh
from candidate
答案 1 :(得分:1)
您可以尝试使用窗口函数-row_number()
select * from
(
Select candidate.id, candidate.firstname +' '+ candidate.lastname as 'Candidate Name', cwh.dateworked,row_number() over(partition by candidate.id order by cwh.dateworked desc) as rn
from candidate inner join canworkhistory cwh
on candidate.id = cwh.candidateid
)X where rn=1
答案 2 :(得分:1)
您可以将派生表与group by
和max
一起使用:
Select candidate.id,
candidate.firstname +' '+ candidate.lastname as 'Candidate Name',
cwh.dateworked
from candidate
inner join (
select candidateid, max(dateworked) as dateworked
from canworkhistory
group by candidateid
) cwh on candidate.id = cwh.candidateid
答案 3 :(得分:1)
您可以尝试以下操作
with cte as
(
Select candidate.id, candidate.firstname +' '+ candidate.lastname
as 'Candidate Name', cwh.dateworked
from candidate
inner join canworkhistory cwh on candidate.id = cwh.candidateid
) select t.* from cte t where t.dateworked =
( select max(dateworked) from canworkhistory t1
where t1.candidateid=t.id
group by candidateid
)
答案 4 :(得分:1)
您也可以尝试使用CTE
;WITH RecentWork
AS (SELECT
candidateid
,max(dateworked)
FROM
canworkhistory
GROUP BY
candidateid)
SELECT
candidate.id
,candidate.firstname + ' ' + candidate.lastname AS 'Candidate Name'
,RecentWork.dateworked
FROM
candidate
INNER JOIN RecentWork
ON candidate.id = RecentWork.candidateid