Chrome控制台中数组的不同表示形式

时间:2018-11-05 07:47:59

标签: javascript arrays google-chrome async-await console.log

这是我的代码

let loadInitialImages = ($) => {
 let html = "";
 let images = new Array();
 const APIURL = "https://api.shutterstock.com/v2/images/licenses";

 const request = async() => {
    const response = await fetch(APIURL, { headers: auth_header() } );
    const json = await response.json();
    json.data.map((v) => images.push(v.image.id)); //this is where the problem is
 }

 request();

 // I can see the contents of the array when I log it.
 console.log(images);
 // But I can't see any elements when logging this way:
 images.map((id) => console.log(id));
}

一切在这里都可以正常工作,但是问题是当我将元素推入数组时,它从数组括号[]中消失了,下面是我的数组的屏幕截图: Array output

我无法在此处遍历数组。

这是控制台中普通阵列的外观 Usual Array

请参阅此处的数组括号。元素似乎在[1, 2, 3]

内部

3 个答案:

答案 0 :(得分:2)

由于您的request函数是async,因此您需要将其结果视为Promise

这也是为什么您在chrome控制台中看到它表示不同的原因。将打印一个空数组,但是控制台中的引用是动态更新的,因此您仍然可以展开它并查看其内容。

如果要静态记录数组的内容,可以使用JSON.stringify之类的东西来打印它。这将在记录日志时打印出表示阵列确切状态的字符串表示形式。

// You will need to check the output in the browser console.
// Your code could be reduced to this:
const a = []; 
setTimeout(() => a.push(1, 2), 100); 
console.log('a:', a);

// A filled array logs differently:
const b = [1, 2]; 
console.log('b:', b);

// Stringify gives you a fixed state:
const c = []; 
setTimeout(() => c.push(1, 2), 100);
console.log('c:', JSON.stringify(c));

关于代码,除了等待request()之外,如果您正在使用map,则应该利用of how it works。您可以使用它来生成整个数组,而无需使用push。如果仍然要使用数组并对其使用push(),则应使用json.data.forEach而不是json.data.map,因为它不会复制数组。

// Making your function `async` so you can `await` for the `request()`
let loadInitialImages = async ($) => {
  let html = "";
  const APIURL = "https://api.shutterstock.com/v2/images/licenses";

  const request = async () => {
    const response = await fetch(APIURL, { headers: auth_header() } );
    const json = await response.json();
    // Array.map will return a new array with the results of applying 
    // the given function to the original array, you can use that as 
    // an easy way to return your desired array.
    return json.data.map((v) => v.image.id); 
  }

  // Since request() is async, you need to wait for it to complete.
  const images = await request();
  // Array.forEach lets you iterate over an array without generating a
  // copy. If you use map here, you would be making an unneeded copy 
  // of your images array.
  images.forEach(i => console.log(i));
}

答案 1 :(得分:-1)

下面的代码段演示了您的问题(您的情况是arr1,您想使用arr2)。
如果loadInitialImages不能async,请使用arr3方案。

async function main(){
let arr1 = [], arr2 = [], arr3 = [];

const getArray = ()=> (new Promise(resolve=>setTimeout(()=>{resolve([1,2,3])},1000)))



async function request(arr, number){
  var result = await getArray();
  result.forEach((el)=>(arr.push(el)))
  console.log(`inner${number}`, arr)
  return result;
}

request(arr1, 1);

console.log("outer1", arr1)

await request(arr2, 2);

console.log("outer2", arr2)

request(arr3, 3).then(()=>{
  console.log("then3",arr3)
})
console.log("outer3", arr3)
}

main();

答案 2 :(得分:-2)

我认为问题在于在填充数组之前会触发console.log(),并且因为console.log使用引用工作,所以它会同时打印数组的状态(当它为空时以及在使用.map填充后) )

您可以测试此代码吗? 控制台就在循环之后

let loadInitialImages = ($) => {
    let html = "";
    let images = new Array();
    const APIURL = "https://api.shutterstock.com/v2/images/licenses";

    const request = async() => {
       const response = await fetch(APIURL, { headers: auth_header() } );
       const json = await response.json();
       json.data.map((v) => images.push(v.image.id)); //this is where the problem is
       console.log(images);
    }

    request();

}

let loadInitialImages = ($) => {
        let html = "";
        let images = new Array();
        const APIURL = "https://api.shutterstock.com/v2/images/licenses";

        const request = async() => {
           const response = await fetch(APIURL, { headers: auth_header() } );
           const json = await response.json();
           json.data.map((v) => images.push(v.image.id)); //this is where the problem is
           console.log(images);
        }

        request();

    }
    
    loadInitialImages();