Question

我是C语言的新手这是我的代码：

#include <stdio.h>

int main(void) {
    int choice;
    int clientNum;
    printf("\nAssume that in the main memory contain 16 frameSize\n");
    printf("Each frame has 256 bits\n");
    printf("How many clients: ");
    scanf("%d", &clientNum);
    printf("\nPlease choose the Scheduling Algorithm 1. FCFS 2.Round Robin: ");
    scanf("%d", &choice);
    while(choice !=1 || choice !=2){
        printf("\nINVALID!!! The Server only has either FCFS or Round Robind Algorithm");
        printf("\nPlease choose the Scheduling Algorithm again 1. FCFS 2.Round Robin: ");
        scanf("%d", &choice);
    }
    if (choice==1){
        printf("FCFS");
    }
    if (choice==2){
        printf("Round Robind");
    }
    return 0;
}

我想将选择的值与数字1和2进行比较。但是，If语句不能正常工作。它没有将选择与任何价值进行比较语法或逻辑上有错误吗？

输出：

gcc version 4.6.3


Assume that in the main memory contain 16 frameSize
Each frame has 256 bits
How many clients:  3

Please choose the Scheduling Algorithm 1. FCFS 2.Round Robin:  1

INVALID!!! The Server only has either FCFS or Round Robind Algorithm
Please choose the Scheduling Algorithm again 1. FCFS 2.Round Robin:  2

INVALID!!! The Server only has either FCFS or Round Robind Algorithm
Please choose the Scheduling Algorithm again 1. FCFS 2.Round Robin:  1

INVALID!!! The Server only has either FCFS or Round Robind Algorithm
Please choose the Scheduling Algorithm again 1. FCFS 2.Round Robin:

Answer 1

 while ((choice !=1) && (choice !=2))
   {    
        code.....
   }

循环后，您将最终得到2个选择，即1或2，因此：

 if (choice == 1)
{
    printf("FCFS");
}
else
{
    printf("Round Robind");

Answer 2

这应该有效：

#include <stdio.h>

int main(void) 
{
    int choice;
    int clientNum;

    printf("\nAssume that in the main memory contain 16 frameSize\n");
    printf("Each frame has 256 bits\n");
    printf("How many clients: ");
    scanf("%d", &clientNum);
    printf("\nPlease choose the Scheduling Algorithm 1. FCFS 2.Round Robin: ");
    scanf("%d", &choice);
    while (choice !=1 && choice !=2)     //change || into &&
    {
        printf("\nINVALID!!! The Server only has either FCFS or Round Robind Algorithm");
        printf("\nPlease choose the Scheduling Algorithm again 1. FCFS 2.Round Robin: ");
        scanf("%d", &choice);
    }
    if (choice == 1)
    {
        printf("FCFS");
    }
    if (choice == 2)
    {
        printf("Round Robind");
    }
    return 0;
}

if陈述式在C中无法正常运作

2 个答案: