我对单元测试还很陌生,因此开始编写一个简单的测试以确保使用assertJ返回的查询不为null。我正在使用Fongo进行单元测试,尽管没有错误,但返回的值始终为null。
这是要测试的课程:
@Repository
public class DataVersionDaoMongo extends MongoBaseDao<DataVersion> implements DataVersionDao {
@Autowired
MongoOperations mongoOperations;
public DataVersionDaoMongo() {
initType();
}
@Override
public DataVersion findByDBAndCollection(String dbName, String collectionName) {
//return mongoOperations.findOne(Query.query(Criteria.where("dbName").is(dbName).and("collectionName").is(collectionName)), DataVersion.class);
Criteria criteria = Criteria.where("dbName").is(dbName).and("collectionName").is(collectionName);
Query query = Query.query(criteria);
return mongoOperations.findOne(query, DataVersion.class);
}
}
这是我的单元测试:
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration("classpath:/testApplicationContext.xml")
public class DataVersionDaoMongoTest {
@Autowired
private DataVersionDaoMongo dataVersionDaoMongo;
//private MongoOperations mongoOperations;
private DataVersion dataVersion;
@Rule
public FongoRule fongoRule = new FongoRule();
@Test
public void findByDBAndCollection() {
String dbname = "mydb";
String collectionName = "mycollection";
DB db = fongoRule.getDB(dbname);
DBCollection collection = db.getCollection(collectionName);
Mongo mongo = fongoRule.getMongo();
collection.insert(new BasicDBObject("name", "randomName"));
assertThat(dataVersionDaoMongo.findByDBAndCollection(dbname, collectionName)).isNotNull();
}
}
我确定
dataVersionDaoMongo.findByDBAndCollection(dbname, collectionName)
返回null(返回DataVersion
对象为null),因此测试失败。我实际上将如何处理并使其返回不为null的DataVersion?
这是DataVersion类:
@Document(collection = "DataVersion")
public class DataVersion {
@Id
private String id;
private String dbName;
private String collectionName;
private String version;
private boolean isCompleted;
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getDbName() {
return dbName;
}
public void setDbName(String dbName) {
this.dbName = dbName;
}
public String getCollectionName() {
return collectionName;
}
public void setCollectionName(String collectionName) {
this.collectionName = collectionName;
}
public String getVersion() {
return version;
}
public void setVersion(String version) {
this.version = version;
}
public boolean isCompleted() {
return isCompleted;
}
public void setCompleted(boolean isCompleted) {
this.isCompleted = isCompleted;
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result
+ ((collectionName == null) ? 0 : collectionName.hashCode());
result = prime * result + ((dbName == null) ? 0 : dbName.hashCode());
result = prime * result + (isCompleted ? 1231 : 1237);
result = prime * result + ((version == null) ? 0 : version.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
DataVersion other = (DataVersion) obj;
if (collectionName == null) {
if (other.collectionName != null)
return false;
} else if (!collectionName.equals(other.collectionName))
return false;
if (dbName == null) {
if (other.dbName != null)
return false;
} else if (!dbName.equals(other.dbName))
return false;
if (isCompleted != other.isCompleted)
return false;
if (version == null) {
if (other.version != null)
return false;
} else if (!version.equals(other.version))
return false;
return true;
}
}
任何帮助将不胜感激!
P.S。
这是我在单元测试课中添加的内容:
@Autowired
private MongoOperations mongoOperations;
然后
DataVersion dataVersion = new DataVersion();
dataVersion.setDbName("DBDataVersion");
dataVersion.setVersion("version1");
dataVersion.setCollectionName("DataVersion");
mongoOperations.insert(dataVersion);
assertThat(dataVersionDaoMongo.findByDBAndCollection(dataVersionDaoMongo.getDbName(), dataVersion.getCollectionName())).isNotNull();
单元测试通过了,因为它不再返回null,但是我不再使用Fongo。我不确定我在做什么是否正确。
答案 0 :(得分:0)
您将文档插入测试中的 mycollection 集合中,但dao查询 DataVersion 集合。
此外,您无需在存储的对象中定义 dbName 和 collectionName ,因此,针对这两个字段的查询不会选择它。