我们有一个这样的表(简化版):
产品:
Itemid Itemname Itemfatherid
itemA theitemA null
itemB theitemB null
itemC theitemC itemA
itemD theitemD itemA
itemE theitemE itemC
itemF theitemF itemE
itemG theitemG itemD
我们需要一个sql查询,它提供以下结果/格式:(更正版本)
Col1 Col2 Col3 Col4
itemA itemC itemE itemF
itemA itemD itemG NULL
itemB NULL NULL NULL
我们的ERP会采用这种结果并将其转换为这样的树形控件:
-itemA
-itemC
-itemE
itemF
-itemD
itemG
itemB
树的级别不固定,因此列数必须是动态的......
CTE有一些方法,但我们还没有达到解决方案:S
http://www.sqlservercurry.com/2009/06/simple-family-tree-query-using.html
此外,我们需要知道树的深度(将其传递给GridControl ...)在此示例中它将为3(它需要最大父级别数 - > -itemA -itemC -itemE )
答案 0 :(得分:3)
create table so1 (Itemid varchar(100), Itemname varchar(100), Itemfatherid varchar(100))
insert so1 select
'itemA','theitemA',null union all select
'itemB','theitemB',null union all select
'itemC','theitemC','itemA' union all select
'itemD','theitemD','itemA' union all select
'itemE','theitemE','itemC' union all select
'itemF','theitemF','itemE' union all select
'itemG','theitemG','itemD'
if OBJECT_ID('tempdb..#tmp') is not null drop table #tmp
;
create table #tmp (
uniqueid uniqueidentifier not null,
level int not null,
itemid varchar(100) null,
primary key clustered(uniqueid, level)
)
;with cte(level, itemid, parentid, uniqueid) as
(
select 1, itemid, itemfatherid, NEWID()
from so1
where not exists (select * from so1 k where k.itemfatherid=so1.itemid)
union all
select cte.level+1, t.itemid, t.itemfatherid, cte.uniqueid
from cte
inner join so1 t on t.Itemid = cte.parentid
)
insert #tmp (uniqueid, level, itemid)
select uniqueid, level, itemid
from cte
option (maxrecursion 1000) -- as required
;
;with tmp as (
select *, newlevel = ROW_NUMBER() over (partition by uniqueid order by level desc)
from #tmp)
update tmp
set level = newlevel
;
declare @sql nvarchar(max), @columns nvarchar(max)
;
set @sql = CONVERT(nvarchar(max), (
select number [data()]
from master..spt_values
where type='P' and number between 1 and (select MAX(level) from #tmp)
order by 1
for xml path('a')))
select @sql = stuff(replace(replace(@sql,'</a><a>','],['),'</a>',']'),1,3,'[')
select @sql = '
select ' + @sql + '
from #tmp
pivot (max(itemid) for level in (' + @sql + ')) v
order by ' + @sql
exec (@sql)
1 2 3 4
itemA itemC itemE itemF
itemA itemD itemG NULL
itemB NULL NULL NULL