Question

我正在尝试访问内存访问的值，但是在打印输出时，我一直在获取地址。

char c[16];

 char copyArray(unsigned char* state, unsigned char* key)
{

    for (int i = 0; i < 16; i++)
    {
        state[i] ^= key[i];
         // c[i] =  state[i];      // this gave me the address
        printf("%02x", state[i]);
    }
        printf("\n");

               memcpy (c, state,16);

    for (int i = 0; i < 16; ++i)
    {


        printf("%02d\n",c[i] );
    }
    printf("\n");

}

此功能在另一个功能中执行10次。我想要实现的是存储上次执行的值而不是地址

Answer 1

谢谢大家！

现在解决了。我将c数组设为无符号，就解决了问题

unsigned char c[16];

char copyArray(unsigned char* state, unsigned char* key)
{

for (int i = 0; i < 16; i++)
{
    state[i] ^= key[i];

    printf("%02x", state[i]);
}

printf("\n");

memcpy (c, state,16);

for (int i = 0; i < 16; ++i)
{
    printf("%02x\n",c[i] );
}
printf("\n");

}

如何在C中获取内存地址的值

1 个答案: