Question

我一直在学校从事此python作业，并且一直被困在这个特定的问题上。从给出的数据中，我想找出节省最多的人。

data = {
'Brad':5000, 
'Greg':8000, 
'Sarah':9000000, 
'Kim':6500000, 
'George':24000, 
'Ben':1000
  }

我的代码：

most_savings = 0

for person, savings in data.items():
    if savings > most_savings:
        most_savings = savings
        print(person,"has the most savings at",savings)

打印输出为：

Brad has the most savings at 5000
Sarah has the most savings at 9000000

所需的输出：

Sarah has the most savings at 9000000

我没有得到想要的输出。我想知道我哪里出错了。在这里需要一些帮助。谢谢

Answer 1

不要循环打印-您将打印“此时”最丰富的一个。

most_savings = 0
pers = None 

# process all data, remembers pers and most_savings    
for person, savings in data.items():
    if savings > most_savings:
        most_savings = savings
        pers = person

 # print only the final result
 print(pers,"has the most savings at",most_savings)

您还可以使用内置的max()函数并指定一个lambda - function作为键函数，以便在决定内容时评估该项目的（键，值）部分max（））：

person, savings  = max( data.items(), key = lambda x:x[1])
print(person,"has the most savings at",savings)

使用循环仅从字典中打印一个键

1 个答案: