Question

我想将其打开（在.txt文件中）：

7316717653
1330624919

（在Python列表中）：

a_list = [7, 3, 1, 6, 7, 1, 7, 6, 5, 3, 1, 3, 3, 0, 6, 2, 4, 9, 1, 9]

我该怎么做？我到处都在看，但是没有什么比我打算做的事

Answer 1

lst = []
with open('New Text Document.txt', 'r') as f: #open the file 
    lines = f.readlines() # combine lines of file in a list
    for item in lines: # iterate through items of  lines
        # iterate through items in each line and remove extra space after last item in the line using strip method
        for digit in item.strip(): 
            lst.append(int(digit)) # append digits in to the list and convert them to int

print(lst)
[7, 3, 1, 6, 7, 1, 7, 6, 5, 3, 1, 3, 3, 0, 6, 2, 4, 9, 1, 9]

Answer 2

java
--mypackage
    --beans
        UserBean.java
    --mapper
        UserMapper.java         
    --service
        UserMapperServer.java
--resources
resources
--mypackage
    --mapper
         UserMapper.xml

Answer 3

这是一个完整的解决方案：

num = '''7316717653
      1330624919'''
num = num.replace('\n', '')
# Write to a text file:
with open('filename.txt', 'w') as f:
    f.write(num)

# Now write to a Python List:
fd = open('filename.txt','rU')
chars = []
for line in fd:
    chars.extend(line)

输出为： [7、3、1、6、7、1、7、6、5、3、1、3、3、0、6、2、4、9、1、9、9]

Python-将多行文本文件读入列表

3 个答案: