我有一个表单,我的用户可以设置条件来搜索其客户数据库,但是为此我正努力将查询汇总到一起(在Laravel 5.7中工作)。
当前客户可以设置的标准如下:
我现在正在设法将其构建为查询的方法,我什至无法给出具体的例子!我的障碍似乎是检查第一个记录和最后一个记录,以确保它符合条件。
SQLFiddle:http://sqlfiddle.com/#!9/68407/1
我的桌子:
| id | name | email | provider | created_at
---------------------------------------------------------------------------------------
| 1 | Mr Smith | mr.smith@example.com | facebook | 2018-11-01 09:00:00 |
| 2 | Mrs Smith | mrs.smith@example.com | facebook | 2018-11-01 09:00:00 |
| 3 | Miss Smith | miss.smith@example.com | email | 2018-11-01 09:00:00 |
| 4 | Doctor Smith | doctor.smith@example.com | email | 2018-11-01 09:00:00 |
| 5 | Lord Smith | lord.smith@example.com | twitter | 2018-11-01 09:00:00 |
| 6 | Lady Smith | lady.smith@example.com | email | 2018-11-01 09:00:00 |
| 7 | Mr Smith | mr.smith@example.com | facebook | 2018-11-02 09:00:00 |
| 8 | Mrs Smith | mrs.smith@example.com | facebook | 2018-11-02 09:00:00 |
| 9 | Doctor Smith | doctor.smith@example.com | email | 2018-11-02 09:00:00 |
| 10 | Lord Smith | lord.smith@example.com | twitter | 2018-11-02 09:00:00 |
| 11 | Lady Smith | lady.smith@example.com | email | 2018-11-02 09:00:00 |
| 12 | Mr Smith | mr.smith@example.com | facebook | 2018-11-03 09:00:00 |
| 13 | Mrs Smith | mrs.smith@example.com | facebook | 2018-11-03 09:00:00 |
| 14 | Miss Smith | miss.smith@example.com | email | 2018-11-03 09:00:00 |
| 15 | Lord Smith | ord.smith@example.com | twitter | 2018-11-03 09:00:00 |
| 16 | Lady Smith | lady.smith@example.com | email | 2018-11-03 09:00:00 |
查询的示例客户条件:
当前查询:
$Customers = Customer::groupBy('email')
->havingRaw('COUNT(*) > 2’)
->where('created_at', '<', Carbon::now()->subDays(2)->toDateTimeString())
->get();
我不知道如何提取第一个客户记录是否已超过2天,然后提取其最后一个记录并确保其已超过1天。 我知道我当前的查询对于我要实现的目标完全没有用,但是我再次努力将其组合在一起。
预期结果:
| id | name | email | provider | created_at
---------------------------------------------------------------------------------------
| 12 | Mr Smith | mr.smith@example.com | facebook | 2018-11-03 09:00:00 |
| 13 | Mrs Smith | mrs.smith@example.com | facebook | 2018-11-03 09:00:00 |
答案 0 :(得分:2)
您要查找的查询是:
select * from customers group by email having count(*) > 2 and min(created_at) <= '2018-10-02 09:00:00' and max(created_at) <= '2018-10-03 09:00:00' and provider = 'facebook'
假设当前时间为2018-10-04 09:00:00。
雄辩地:
$Customers = Customer::groupBy('email')
->havingRaw('COUNT(*) > 2')
->havingRaw('max(created_at) < ?' , [Carbon::now()->subDays(2)->toDateTimeString()])
->havingRaw('min(created_at) < ?' , [Carbon::now()->subDays(1)->toDateTimeString()])
->havingRaw('provider = ?' , ['facebook'])
->get();
在单独的注释上,您可以使用雄辩的方法链接方法,如下所示:
$customers = Customer::groupBy('email');
if( $includeCount ) {
$customers->havingRaw('COUNT(*) > 2');
}
...
...
...
答案 1 :(得分:1)
MySQL方言中进行选择的SQL查询如下
SELECT id, name, email, provider, created_at
FROM customers
WHERE provider = 'facebook'
GROUP BY email
HAVING
count(*) > 2
AND min(created_at) < date_sub(now(), interval 2 day)
AND max(created_at) < date_sub(now(), interval 1 day)
那可以翻译成雄辩的查询
$havingClause = 'count(*) > ? AND min(created_at) < ? AND max(created_at) < ?';
$havingClauseBindings = [
2,
Carbon::now()->subDays(2)->toDateTimeString(),
Carbon::now()->subDays(1)->toDateTimeString()
];
$customers = Customer::where('provider', 'facebook')
->groupBy('email')
->havingRaw($havingClause, $havingClauseBindings)
->get();