有没有办法让“ self”在执行方法的地方？

Question

我有此代码：

import time
import tensorflow as tf

input_data = tf.constant([[1.,1.]])
output_data = tf.constant([[1.,0.]])
weight = tf.Variable([[1.,1.],
                      [1.,1.]])

optimizer = tf.train.GradientDescentOptimizer(0.1)
y = tf.matmul(input_data, weight)
loss = (output_data[0][0] - y[0][0])**2 + (output_data[0][1] - y[0][1])**2
train = optimizer.minimize(loss)

with tf.Session() as sess:
    sess.run(tf.global_variables_initializer())
    print('Initial weights: ', sess.run(weight))
    for epoch in range(1000):
        st = time.time()
        sess.run(train)
        print('Epoch %3d : %.3f ms' %(epoch, 1e3*(time.time()-st)))
    print('Weights: ', sess.run(weight))

我想做类似的事情：

class Foo
  def run(scope:)
     p scope
  end
end

module Bar
  Foo.run(scope: self) # >> Bar
end

Foo.run(scope: self) # >> main

具有相同的结果。有没有一种方法可以在不显式提及该方法的情况下获得调用方法的module Bar Foo.run end Foo.run ？