我正在编写一个函数,该函数带有多个参数,字符串或字符串向量,这些参数,字符串或向量与要过滤的属性相对应。我还想编写函数,以便在未指定过滤器属性的情况下,将其忽略,而其他过滤器属性也可以工作。
为什么使用quo
的速记不能以这种方式工作,如何更改它以使其起作用?
library(dplyr); library(datasets)
filterhec <- function(hair = '', eyecolor = '', sex = '') {
hec <- as.data.frame(datasets::HairEyeColor)
# Filter condition variable, which changes depending on parameters
fcond <- quo(
(ifelse(hair == '', 1, Hair == hair)) &
(ifelse(all(eyecolor == ''), 1, Eye %in% eyecolor)) &
(ifelse(sex == '', 1, Sex == sex)))
filter(hec, !!fcond)
}
filterhec(hair = 'Black', eye = c('Brown', 'Blue'))
# Hair Eye Sex Freq
# 1 Black Brown Male 32
# 2 Brown Brown Male 53
# 3 Red Brown Male 10
# 4 Blond Brown Male 3
# 5 Black Blue Male 11
# 6 Brown Blue Male 50
# 7 Red Blue Male 10
# 8 Blond Blue Male 30
# 9 Black Hazel Male 10
#
# ^Expected dataframe where Hair is always 'Black' and Eye is 'Brown' or 'Blue'
答案 0 :(得分:0)
函数的参数已被引用为字符向量,并且对要过滤的变量也进行了硬编码。因此,我认为不需要quo
。您可以这样做:
library(dplyr)
library(datasets)
filterhec <- function(hair = NULL, eyecolor = NULL, sex = NULL) {
hec <- as.data.frame(datasets::HairEyeColor)
filter(
hec,
if (is.null(hair)) 1 else Hair == hair,
if (is.null(eyecolor)) 1 else Eye %in% eyecolor,
if (is.null(sex)) 1 else Sex == sex
)
}
filterhec(hair = 'Black', eye = c('Brown', 'Blue'))
#> Hair Eye Sex Freq
#> 1 Black Brown Male 32
#> 2 Black Blue Male 11
#> 3 Black Brown Female 36
#> 4 Black Blue Female 9