我不知道我是否做对了。我有2个表格Property和PropertyTypes。每个属性都有1个PropertyType。我正在使用外键约束。但是在创建控制器时,我已经收到此错误: “找不到源类型'DbSet'的查询模式的实现。'找不到连接'
请在下面查看我的代码:
[Table("Property.Property")]
public class Property
{
[Key]
public int PropertyId { get; set; }
[StringLength(50)]
public string PropertyName { get; set; }
public int? Owner { get; set; }
public string Cluster { get; set; }
public string PropertyNumber { get; set; }
public string RegionCode { get; set; }
public string ProvinceCode { get; set; }
public string MunicipalCode { get; set; }
public string BarangayCode { get; set; }
public DateTime? DateAdded { get; set; }
public DateTime? DateModified { get; set; }
public int PropertyTypeId { get; set; }
public PropertyType PropertyType { get; set; }
[NotMapped]
public string Type { get; set; }
}
[Table("Property.Types")]
public class PropertyType
{
[Key]
public int PropertyTypeId { get; set; }
[StringLength(50)]
public string Type { get; set; }
public DateTime? DateAdded { get; set; }
public DateTime? DateModified { get; set; }
public List<Property> Properties { get; set; }
}
public class ApplicationDbContext : IdentityDbContext<ApplicationUser>
{
public ApplicationDbContext()
: base("DefaultConnection", throwIfV1Schema: false) {}
// DB Sets
public DbSet<Property> Properties { get; set; }
public DbSet<PropertyType> PropertyTypes { get; set; }
}
控制器
public class PropertyController : ApiController
{
[HttpGet]
[Authorize]
[Route("api/getproperties")]
public async Task<List<Property>> GetProperties()
{
using(var db = new ApplicationDbContext())
{
var properties = await (from p in db.Properties
join pt in db.PropertyTypes
on p.PropertyTypeId equals pt.PropertyTypeId
select new
{
PropertyId = p.PropertyId,
PropertyName = p.PropertyName,
Owner = p.ProertyOwner,
Cluster = p.Cluster,
PropertyNumber = p.PropertyNumber,
RegionCode = p.RegionCode,
ProvinceCode = p.ProvinceCode,
MunicipalCode = p.MunicipalCode,
BarangayCode = p.BarangayCode,
DateAdded = p.DateAdded,
DateModified = p.DateModified,
PropertyTypeId = p.PropertyTypeId,
type = pt.Type
}
).ToListAsync();
return properties;
}
}
}
您能告诉我正确的方法吗?谢谢。