破坏两个PHP数组与以下条件

Question

我有两个学生和标记。需要一个marks_sheet之类的输出数组。删除marks数组中不存在的所有数据，并插入一个新的字段marks。 //此数组的名称学生

Array    
    (
        [0] => Array
            (
                [userId] => user1
                [name] => Suman Mandal
                [age] => 20    

            )
        [1] => Array
            (

                [userId] => user2
                [name] => Amit Halder
                [age] => 30

            )
        [2] => Array
            (

                [userId] => user3
                [name] => Asif Rahman
                [age] => 25

            )
        [3] => Array
            (

                [userId] => user4
                [name] => Gopal Ghosh
                [age] => 21

            )
    )

//此数组的名称标记

 Array   
    (
        [0] => Array
            (
                [userId] => user1 
                [marks]=>80 

            )
        [1] => Array
            (

                [userId] => user3  
                [marks]=>90          
            )

    )

我需要这样的输出： //此数组的名称 marks_sheet

 Array   
    (
        [0] => Array
            (
                [userId] => user1 
                [name] => Suman Mandal
                [age] => 20
                [marks]=>80 

            )
        [1] => Array
            (

                [userId] => user3  
                [name] => Asif Rahman
                [age] => 25
                [marks]=>90          
            )

    )

我对php有一点了解。也许这很简单，但是我很难解决...请帮助我

Answer 1

您可以在userId索引数组上使用array_replace_recusrive。

首先使用array_column通过userId索引数组。

然后使用array_replace_recursive合并数组中的值并保留两个数组集的键索引。

最后使用array_intersect_key仅从$marks数组返回数组值。

示例https://3v4l.org/adrYV

$students = array_column($students, null, 'userId');
$marks = array_column($marks, null, 'userId');
$marks_sheet = array_intersect_key(array_replace_recursive($students, $marks), $marks);

结果

Array
(
    [user1] => Array
        (
            [userId] => user1
            [name] => Suman Mandal
            [age] => 20
            [marks] => 80
        )

    [user3] => Array
        (
            [userId] => user3
            [name] => Asif Rahman
            [age] => 25
            [marks] => 90
        )

)

如果您不希望最终结果被userId索引，则可以使用array_values，它将为数组重新索引。

$marks_sheet = array_values(
    array_intersect_key(array_replace_recursive($students, $marks), $marks)
);

结果

Array
(
    [0] => Array
        (
            [userId] => user1
            [name] => Suman Mandal
            [age] => 20
            [marks] => 80
        )

    [1] => Array
        (
            [userId] => user3
            [name] => Asif Rahman
            [age] => 25
            [marks] => 90
        )

)

---

或者，您可以遍历标记和学生以构建marks_sheet数组。

示例https://3v4l.org/Xmg3a

$marks_sheet = [];
foreach ($marks as $mark) {
    foreach ($students as $student) {
        if ($student['userId'] === $mark['userId']) {
            $mark_sheet = $student;
            foreach ($mark as $key => $value) {
                $mark_sheet[$key] = $value;
            }
            $marks_sheet[] = $mark_sheet;
        }
    }
}

结果

Array
(
    [0] => Array
        (
            [userId] => user1
            [name] => Suman Mandal
            [age] => 20
            [marks] => 80
        )

    [1] => Array
        (
            [userId] => user3
            [name] => Asif Rahman
            [age] => 25
            [marks] => 90
        )

)