Question

我使用Selenium抓取网站并获取相关数据。我写了以下脚本：

def scrap_understat(bot_function):
   init_db_connection()
   init_browser('firefox')

   for i in range(7240, 8000):
        try:
            driver.get('https://understat.com/player/' + str(i))
            while not wait_for_element(driver, By.ID, 'header'):
                driver.get('https://understat.com/player/' + str(i))
            time.sleep(1)
            if try_find_Element(driver, By.CLASS_NAME, 'error-code') is not None:
                continue
            player_name = driver.find_element(By.CLASS_NAME, 'header-wrapper').text
            current_team = driver.find_element(By.CLASS_NAME, 'breadcrumb').find_elements(By.TAG_NAME, 'li')[-2].text
            data = get_player_data(player_name, current_team)
            save_data(data)

        except Exception as ex:
            log_this(ex)
            print(str(ex))

但是，脚本会因第一个“错误”而停止： https://understat.com/player/7245

很显然，此页面包含错误代码类。如果检查页面，则会看到以下

span class =“ error-code”> 404

例如，在https://understat.com/player/7245上不存在此类。我使用continue命令转到下一个迭代。但是，浏览器在https://understat.com/player/7245上冻结。我究竟做错了什么？

预先感谢

无法跳至for循环语句中的下一个迭代

0 个答案: