Question

表架构

CREATE TABLE `shops` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `user_id` int(11) DEFAULT NULL,
  `shop_code` varchar(60) COLLATE utf8mb4_unicode_ci NOT NULL,
  `retailer_name` varchar(100) COLLATE utf8mb4_unicode_ci DEFAULT NULL,
  `shop_closed_temporarily` tinyint(4) NOT NULL DEFAULT '0',
  `verification_status` tinyint(4) NOT NULL DEFAULT '0' COMMENT '0=no-action,1=verified,2=rejected,3=pending',
  PRIMARY KEY (`id`)
)

表中的数据

id user_id shop_code retailer_name shop_closed_temporarily verification_status
1 3 XYZ0001 abc 0 3
2 3 XYZ0002 abd 0 3
3 3 XYZ0003 abe 1 2
4 3 XYZ0004 abf 0 1
5 3 XYZ0005 abf 0 3
6 3 XYZ0005 abf 0 3

问题：

我想获取所有不同的“ shop_code”记录，其中verification_status = 3，shop_closed_temporarily = 0。结果应为所有列。

查询

SELECT
  *
FROM
  shops s
WHERE s.user_id = 3
  AND s.shop_closed_temporarily = 0
  AND s.verification_status = 3
GROUP BY s.shop_code

想要实现： 1,2,5 要么 1,2,6 因为第5行和第6行具有相似的shop_code。

Answer 1

您可以使用聚合函数，例如min（）

select min(s.id), s.shop_code 
FROM  shops s
WHERE s.user_id = 3
  AND s.shop_closed_temporarily = 0
  AND s.verification_status = 3
GROUP BY s.shop_code

或max（）

select max(s.id), s.shop_code 
FROM
  shops s
WHERE s.user_id = 3
  AND s.shop_closed_temporarily = 0
  AND s.verification_status = 3
GROUP BY s.shop_code

以及所有列

要获取所有列，您可以使用检索到的id（my_id）将合并查询与表本身的结果联接起来，例如：for max（s.id）

select s1.* from shops s1
inner join 
(
    select max(s.id) my_id, s.shop_code 
    FROM
      shops s
    WHERE s.user_id = 3
      AND s.shop_closed_temporarily = 0
      AND s.verification_status = 3
    GROUP BY s.shop_code 
) t on t.my_id = s1.id

Answer 2

尝试使用不同的

SELECT DISTINCT shop_code  FROM `shops`;

返回

 shop_code
 XYZ0001
 XYZ0002
 XYZ0003
 XYZ0004
 XYZ0005

MySQL选择没有分组依据的列

2 个答案: