Question

MySQL查询：

SELECT categories.name AS CATEGORIES,GROUP_CONCAT(subcategories.name) AS 
SUBCATEGORIES FROM subcategories INNER JOIN categories ON 
subcategories.categorieName = categories.name GROUP BY categories.name;

Answer 1

对于已经准备好的SQL查询，您可以使用函数sequelize.query

您可以尝试：

sequelize.query("SELECT categories.name AS CATEGORIES,GROUP_CONCAT(subcategories.name) AS SUBCATEGORIES FROM subcategories INNER JOIN categories ON subcategories.categorieName = categories.name GROUP BY categories.name")
.spread((results, metadata) => {
  // Results will be an empty array
  // and metadata will contain the number of affected rows.
})

您的参考，以获取更多详细信息：

http://docs.sequelizejs.com/manual/tutorial/raw-queries.html

我希望对您有帮助

我是sequelize的新手，如何将mysql查询转换为sequelize

1 个答案: