Question

return arg.reduce((prev, current) => prev + current)

我要列出动画列表

但是有问题

如果我尝试使用此代码，则每年只有四分之一的ID

例如，如果我将这4个动画添加到列表中

cur.execute('''
CREATE TABLE IF NOT EXISTS Title (
    id INTEGER UNIQUE PRIMARY KEY AUTOINCREMENT NOT NULL,
    t_name TEXT UNIQUE,
    genre_id INTEGER,
    production_id INTEGER,
    year_id INTEGER
)''')
cur.execute('''
CREATE TABLE IF NOT EXISTS Genre (
    id INTEGER UNIQUE PRIMARY KEY AUTOINCREMENT NOT NULL,
    g_name TEXT UNIQUE
)''')
cur.execute('''
CREATE TABLE IF NOT EXISTS Production (
    id INTEGER UNIQUE PRIMARY KEY AUTOINCREMENT NOT NULL,
    p_name TEXT UNIQUE
)''')
cur.execute('''
CREATE TABLE IF NOT EXISTS Year (
    id INTEGER UNIQUE PRIMARY KEY AUTOINCREMENT NOT NULL,
    year TEXT UNIQUE,
    quater_id INTEGER
)''')
cur.execute('''
CREATE TABLE IF NOT EXISTS Quater (
    id INTEGER UNIQUE PRIMARY KEY AUTOINCREMENT NOT NULL,
    quater TEXT UNIQUE
)''')

while True:
    i_title = input('Insert title: ')
    i_genre = input('Insert genre: ')
    i_production = input('Insert production: ')
    i_year = input('Insert year: ')
    i_quater = input('Insert quater: ')


    try:
        cur.execute('''INSERT OR IGNORE INTO Quater (quater) VALUES (?)''', (i_quater,))
        f_quater = cur.execute("SELECT id From Quater WHERE quater = ?", [i_quater]).fetchone()[0]

        cur.execute('''INSERT OR IGNORE INTO  Year (year, quater_id) VALUES (?,?)''', (i_year, f_quater))
        f_year = cur.execute("SELECT id From Year WHERE year = ?", [i_year]).fetchone()[0]

        cur.execute('''INSERT OR IGNORE INTO Production (p_name) VALUES (?)''', (i_production,))
        f_production = cur.execute("SELECT id From Production WHERE p_name = ?", [i_production]).fetchone()[0]

        cur.execute('''INSERT OR IGNORE INTO Genre (g_name) VALUES (?)''', (i_genre,))
        f_genre = cur.execute("SELECT id From Genre WHERE g_name = ?", [i_genre]).fetchone()[0]


        cur.execute('''INSERT INTO Title (t_name, genre_id, production_id, year_id ) VALUES (?,?,?,?)''', (i_title, f_genre, f_production, f_year ))


        conn.commit()
        print('Data is inserted')

结果在“标题表”中是这样的

animation1, genre, production, 2018(year_id = 1), 4 quarter(quarter_id = 1)
animation2, genre, production, 2018(year_id = 1), 3 quarter(quarter_id = 2)
animation3, genre, production, 2018(year_id = 1), 2 quarter(quarter_id = 3)
animation4, genre, production, 2018(year_id = 1), 1 quarter(quarter_id = 4)

和“年表”

中

---t_name-----genre_id--production_id-year_id------
 animation1   genre_id  production_id   1
 animation2                             1
 animation3                             1
 animation4                             1

和“季度表”中

id---year---quarter_id
1    2018       1

我想要这样的Year表中有4条记录

id---qurter---
1       4
2       3
3       2
4       1

所以当我连接所有表时，它显示如下

id---year---quarter_id
1    2018       1
2    2018       2
3    2018       3
4    2018       4

对不起，我不是英语母语人士，但希望您能理解我的意思

（python3，sqlite3）插入或忽略问题

0 个答案: