我正尝试使用以下代码使用HTMLUnit 2.32下载ZIP文件。
我获得的“ myfile.zip”大于通过普通浏览器下载的文件(179kb与79kb),并且该文件已损坏。
如何点击锚点并使用HTMLUnit下载文件?
WebClient wc = new WebClient(BrowserVersion.CHROME);
final String HREF_SCARICA_CONSOLIDATI = "/web/area-pubblica/quotate?viewId=export_quotate";
final String CONSOBBase = "http://www.consob.it";
HtmlPage page = wc.getPage(CONSOBBase + HREF_SCARICA_CONSOLIDATI);
final String downloadButtonXpath = "//a[contains(@href, 'javascript:downloadAzionariato()')]";
List<HtmlAnchor> downloadAnchors = page.getByXPath(downloadButtonXpath);
HtmlAnchor downloadAnchor = downloadAnchors.get(0);
UnexpectedPage downloadedFile = downloadAnchor.click();
InputStream contentAsStream = downloadedFile.getWebResponse().getContentAsStream();
File destFile = new File("/tmp", "myfile.zip");
Writer out = new OutputStreamWriter(new FileOutputStream(destFile));
IOUtils.copy(contentAsStream, out);
out.close();
答案 0 :(得分:1)
已对代码段进行了一些更新以使其正常运行。希望内联注释有助于了解发生了什么(使用HtmlUnit的最新SNAPSHOT代码(2.34-SNAPSHOT 2018/11/03)
final String HREF_SCARICA_CONSOLIDATI = "http://www.consob.it/web/area-pubblica/quotate?viewId=export_quotate";
try (final WebClient webClient = new WebClient(BrowserVersion.FIREFOX_60)) {
HtmlPage page = webClient.getPage(HREF_SCARICA_CONSOLIDATI);
final String downloadButtonXpath = "//a[contains(@href, 'javascript:downloadAzionariato()')]";
List<HtmlAnchor> downloadAnchors = page.getByXPath(downloadButtonXpath);
HtmlAnchor downloadAnchor = downloadAnchors.get(0);
// click does some javascript magic - have a look at your browser
// seems like this opens a new window with the content as response
// because of this we can ignore the page returned from click
downloadAnchor.click();
// instead of we are waiting a bit until the javascript is done
webClient.waitForBackgroundJavaScript(1000);
// now we have to pick up the window/page that was opened as result of the download
Page downloadPage = webClient.getCurrentWindow().getEnclosedPage();
// and finally we can save to content
File destFile = new File("/tmp", "myfile.zip");
try (InputStream contentAsStream = downloadPage.getWebResponse().getContentAsStream()) {
try (OutputStream out = new FileOutputStream(destFile)) {
IOUtils.copy(contentAsStream, out);
}
}
System.out.println("Output written to " + destFile.getAbsolutePath());
}
答案 1 :(得分:0)
尽管对RBRi的考虑很有趣,但是我发现我的代码可以在不修改的情况下使用HTMLUnit 2.32,但是我以错误的方式编写了文件!
我用过
Writer out = new OutputStreamWriter(new FileOutputStream(destFile));
IOUtils.copy(contentAsStream, out);
它必须是(没有OutputStreamWriter)
FileOutputStream out = new FileOutputStream(destFile);
IOUtils.copy(contentAsStream, out);