Question

我收到此查询的原因是要获取从一年的第一天（2018年1月1日）到明年年末（2019年12月31日）的所有日期。

SELECT MYDATE,
TO_CHAR(NR_OF_SUNDAYS + 1,'FM09') WEEK_NUM,
FROM
(
SELECT MYDATE,
( (TRUNC(MYDATE,'DAY') - TRUNC(TRUNC(MYDATE,'YYYY'),'DAY')) / 7 ) +
CASE WHEN TO_CHAR(TRUNC(MYDATE,'YYYY'),'DAY') = 'SUN' THEN 1 ELSE 0 END AS NR_OF_SUNDAYS
FROM
( SELECT TRUNC (SYSDATE, 'YY') - 1 + LEVEL AS MYDATE
FROM DUAL
CONNECT BY LEVEL <= TRUNC (ADD_MONTHS (SYSDATE, 24), 'YY') -
TRUNC (SYSDATE, 'YY')
)
)

我需要指定以下情况的列：

1）MYDATE
2）如果我当前=
3）如果我当前一周+一周 “下一周”（不包括PAST DUE）
4）其他未来

非常感谢您的帮助。

Answer 1

因此，在我的回答中，我尝试保留您周数计算背后的逻辑。

但是请记住，您可以使用oracle to_char(date,'WW')，to_char(date,'IW')，to_char(date,'W')函数来计算周数，这样您的生活会更加轻松。

WW  Week of year (1-53) where week 1 starts on the first day of the year and continues to the seventh day of the year.
W   Week of month (1-5) where week 1 starts on the first day of the month and ends on the seventh.
IW  Week of year (1-52 or 1-53) based on the ISO standard.

说了这么多，这就是我基于您的计算方法仅使用sql的解决方案（请注意，定义和使用函数会容易得多）。

with date_table as (
SELECT MYDATE, to_number(TO_CHAR(NR_OF_SUNDAYS + 1,'FM09')) WEEK_NUM,  to_number(to_char(MYDATE+1,'IW')) as nu
FROM
(
SELECT MYDATE,
( (TRUNC(MYDATE,'DAY') - TRUNC(TRUNC(MYDATE,'YYYY'),'DAY')) / 7 ) +
CASE WHEN TO_CHAR(TRUNC(MYDATE,'YYYY'),'DY', 'NLS_DATE_LANGUAGE = american') = 'SUN' THEN 1 ELSE 0 END AS NR_OF_SUNDAYS
FROM
( SELECT TRUNC (SYSDATE, 'YY') - 1 + LEVEL AS MYDATE
FROM DUAL
CONNECT BY LEVEL <= TRUNC (ADD_MONTHS (SYSDATE, 24), 'YY') -TRUNC (SYSDATE,'YY')
)
)
),
todays_week as 
(
select distinct WEEK_NUM from date_table 
where trunc(sysdate)=trunc(mydate)
),
pre_final as (
select MYDATE,WEEK_NUM, (select  WEEK_NUM from todays_week) as todaysweek from date_table)
select MYDATE,sysdate,WEEK_NUM,todaysweek,
case when trunc(MYDATE) < trunc(sysdate) then 'PAST DUE' 
     when todaysweek = WEEK_NUM and abs(MYDATE-sysdate)<=7 then 'CURRENT WEEK'
     when todaysweek +1 = WEEK_NUM and abs(MYDATE-sysdate)<=14 then 'Next Week'
     else 'Future' end as description
     from pre_final;

主要思想是找到今天的星期几，然后使用case when。

这是我与结果有关的小提琴。 http://sqlfiddle.com/#!4/3149e4/148

编辑1 ：现在，类似的结果可以达到以下目的：

select res.*,
case when trunc(MYDATE) < trunc(sysdate) then 'PAST DUE' 
     when todaysweek = WEEK_NUM and abs(MYDATE-sysdate)<=7 then 'CURRENT WEEK'
     when todaysweek +1 = WEEK_NUM and abs(MYDATE-sysdate)<=14 then 'Next Week'
     else 'Future' end as description
 from (
SELECT MYDATE, to_number(to_char(MYDATE,'IW')) as WEEK_NUM,to_number(to_char(sysdate,'IW')) as todaysweek 
FROM
( SELECT TRUNC (SYSDATE, 'YY') - 1 + LEVEL AS MYDATE
FROM DUAL
CONNECT BY LEVEL <= TRUNC (ADD_MONTHS (SYSDATE, 24), 'YY') -TRUNC (SYSDATE,'YY')
)) res

基于周号ORACLE的当前状态

1 个答案: