Question

考虑如下查询：

select 
    row_to_json(t) 
from (
    select 
        tablex.id, 
        valuetable.id as "valuetable.id",
        valuetable.val_string as "valuetable.val_string" 
    FROM TableA AS tablex 
    INNER JOIN TableB AS valuetable ON tablex.id = valuetable.id  
    WHERE tablex.code= '123')t;

当从postgres命中时，返回的响应为

{id:111,valuetable.id:222,valuetable.val_string:"xx"}

当我运行相同的查询时：

select 
    tablex.id,
    valuetable.id as "valuetable.id",
    valuetable.val_string as "valuetable.val_string" 
FROM TableA AS tablex 
INNER JOIN TableB AS valuetable ON tablex.id = valuetable.id  
WHERE tablex.code= '123'

带有sequelize，它的响应为

当我运行相同的查询时：

{id:111,valuetable:{id:222,val_string:"xx"}}

这是预期的。

请问您也喜欢如何从postgres生成这样的响应，还是需要从Java端进行任何操作？

Answer 1

尝试使用 json_build_object 代替row_to_json，如下所示：

select 
   json_build_object(
       'id', tablex.id, 
       'valuetable', json_build_object(
           'id', valuetable.id,
           'val_string', valuetable.val_string)
   )
FROM TableA AS tablex 
INNER JOIN TableB AS valuetable ON tablex.id = valuetable.id  
WHERE tablex.code= '123'

Postgres Select查询-分组相同的对象

1 个答案: