解析数组时如何简化if..else语句

Question

我有一个过滤对象数组并将其简化为一个String的函数。数组具有以下格式：

[Person(destination: “city”, surname: [“sur”, “name”]]

此功能可过滤人员以按特定名称查找姓氏。

我有三种名称状态：“约翰”，“保罗”，“詹姆斯”。我想验证每个名字是否存在，并用他的姓氏做些什么。我如何不使用if ... else来做到这一点。我不喜欢这一切的样子。

 enum Destination: String, RawRepresentable {
    case city
    case rural
    case both
}


func findPerson(person: persons, type: Destination) -> String? {
        let surname = persons.filter{ $0.destination == type.rawValue}.reduce("") { id, element in
            return element.details.joined(separator: " ")
        }
         return surname
    }


func findPersons(person: persons) {
        // Also I want to verify if is not null the string that i receive

        if let city = self.findPerson(person: person, type: .city) {
            self.handleCity(type: city)
        }
        if let rural = self.findPerson(person: person, type: .rural) {
            self.handleRural(type: rural)
        }
        if let both = self.findPerson(person: person, type: .both) {
            self.handleBoth(type: both)
        }

    }

Answer 1

 enum Destination: String, RawRepresentable {
    case city
    case rural
    case both

 static let all : [Destination] = [
            .city,
            .rural,
            .both
        ]


 func findPersons(person: persons) {
        // Also I want to verify if is not null the string that i receive

        for destination in Destination.all{
            if let findPerson(person, type: destination){
                self.handleCity(type: destination.rawValue)
            }
        }

    }