Question

我正在尝试执行子手游戏，但问题是客户只是将自己的消息当作消息。如何获得等待消息以仅接受某些用户的输入？

到目前为止，这是我的代码：

@client.command()
async def hangman():
    guess = ""
    hp = 6
    word = "Banana"
    slot = slotMaker(word, guess)
    await client.say("Let`s play the hangman! \n The word is a fruit \n" + slot)
    while slot != word and hp > 0:
        guess += client.wait_for_message()
        slot = slotMaker(word, guess)
        await client.say(slot)
        if letterChecker(word, guess):
            pass
        else:
            hp -= 1
            await client.say("Your hp is now " + str(hp) + ".")

编辑：以下是在不和谐频道中发送的消息：

Esdver9000Today at 11:58 PM
!hangman
sawg112BOTToday at 11:58 PM
Let`s play the hangman! 
 The word is a fruit 
------
-anana
Your hp is now 5.
-anana
Your hp is now 4.
-anana
Your hp is now 3.
-anana
Your hp is now 2.
-anana
Your hp is now 1.
-anana

Answer 1

Client.wait_for_message有一个可选的author参数，您可以使用该参数来接受来自调用命令的人的消息。您可能还应该提供一个channel参数，以免使用用户在其他渠道中发送的消息。

msg = await client.wait_for_message(author=ctx.message.author, channel=ctx.message.channel)

如果您想接受来自非client以外的任何用户的消息，则可以为check编写一个wait_for_message，例如：

check = lambda message: message.author != client.user
msg = await client.wait_for_message(check=check)

如何在wait_for_message（）函数中忽略来自客户端的消息？

1 个答案: