Question

很抱歉无法正确解释。

reel = ["c", "a", "c", "c", "a", "c", "d", "d", "b", "b", "b", "b", "a", 
"b"]
outcome = ["A","A",0,0,0,0,0,0,"A","A"]
x = randint(0, len(reel1)-1)

让我们说x = len（reel1）-2。我们希望通过reel [len（reel1）-2]，reel [len（reel1）-1]，reel [0]等感受“结果”中的所有0。只是x中0的数量会变化，我需要一个通用方法。

Answer 1

我想我了解您在这里要做什么；

say卷轴= [0,1,2,3,4,5,6,7] 您想要得到结果= [6,7,0,1,2,3,4,5]

这项工作吗？

from random import randint
reel = [0,1,2,3,4,5,6,7]

start = randint(min(reel),max(reel))

outcome = reel[start:]
outcome.extend(reel[:start])

Answer 2

不确定我是否理解正确，但这可能会有所帮助：

from random import randrange
x = [1,2,3,4,5,6]
start = randrange(len(x))   # 2
o = x[start:] + x[:start]   # [3, 4, 5, 6, 1, 2]