如何循环编码以再次播放猜测数字？

Question

该代码很好，但是我试图使该代码要求播放器再次播放，这是如果播放器想要再次播放，则该代码将继续运行。但是，这没有发生。

package exercise;

import javax.swing.JOptionPane;
import java.util.Random;

public class guessing_game {

public static void main(String[] args) {
    Random random = new Random();
    int randomNumber = random.nextInt(101);
    boolean userCorrect = false;
    String userInputString;
    int userGuessedNumber;
    int count = 0;
    String play= "n", UserCorrect="y" ;

    do {
        count=count+1;
        userInputString =JOptionPane.showInputDialog("Guess the number:");
        userGuessedNumber =Integer.parseInt( userInputString );

        if( userGuessedNumber > randomNumber) {
            JOptionPane.showMessageDialog( null,  "Too high, try again");
        }

        else if( userGuessedNumber < randomNumber) {
            JOptionPane.showMessageDialog( null,  "Too low, try again");
        }

        else {
            JOptionPane.showMessageDialog( null,  "Yes, you guessed the number, the guessed number is: " + randomNumber);
            JOptionPane.showMessageDialog( null,  "The number your guessed is " + count);
            userCorrect =true;
            play = JOptionPane.showInputDialog("Play again? (y/n) : ");
        }
    }

    while( userCorrect!=true || play == UserCorrect);

}

}

Answer 1

您正在尝试将两个字符串与==进行比较。在大多数情况下，它将始终返回false。

如果要比较两个字符串，请使用.equals(String)函数。

为您，将play == UserCorrect更改为play.equals(UserCorrect)。