Question

如何使用python xml.etree.ElementTree通过正确的xpath获取值

这是'soap.xml'文件

    <?xml version="1.0" encoding="UTF-8"?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <soapenv:Header>
        <platformMsgs:documentInfo xmlns:platformMsgs="urn:messages_2014_1.platform.webservices.netsuite.com">
            <platformMsgs:nsId>WEBSERVICES_3883026_SB1_103120188552030381995151284_f039e9cc</platformMsgs:nsId>
        </platformMsgs:documentInfo>
    </soapenv:Header>
    <soapenv:Body>
        <searchResponse xmlns="urn:messages_2014_1.platform.webservices.netsuite.com">
            <platformCore:searchResult xmlns:platformCore="urn:core_2014_1.platform.webservices.netsuite.com">
                <platformCore:status isSuccess="true"/>
                <platformCore:totalRecords>200</platformCore:totalRecords>
                <platformCore:pageSize>1000</platformCore:pageSize>
                <platformCore:totalPages>1</platformCore:totalPages>
                <platformCore:pageIndex>1</platformCore:pageIndex>
                <platformCore:searchId>WEBSERVICES_3883026_SB1_103120188552030381995151284_f039e9cc</platformCore:searchId>
            </platformCore:searchResult>
        </searchResponse>
    </soapenv:Body>
</soapenv:Envelope>

这是我的代码。

    import xml.etree.ElementTree as ET
    tree = ET.parse('soap.xml') 
    print  tree.findall('.//{http://schemas.xmlsoap.org/soap/envelope/}platformCore')

但是它返回[]而不是value ='200'

Answer 1

您需要使用正确的名称空间（nsmap），然后可以使用前缀轻松进行搜索：

from lxml import etree
tree = etree.parse('soap.xml')
nsmap = {'platformCore': 'urn:core_2014_1.platform.webservices.netsuite.com'}
print (tree.findall('.//platformCore:totalRecords', nsmap)[0].text)

返回：

如何使用python：xml.etree.ElementTree在soap响应中从多个名称空间获取数据

1 个答案: