Question

基本上，我要实现的是遍历json对象，查找是否有具有相同product_id的对象，以及是否应该对这些对象的数量求和。代码：

$data = [];
$objects = $this->reports()->getBasicMeans($this->id)->get();
foreach($objects as $object)
{
    $data[] = $object->json;
}

$json['meanings'] = $data;

这是我编写查询的方式：

public function scopegetBasicMeans($query, $market = null)
{
    $query->where('market_id', $market)->where('type', 1)
        ->join('product_assets', 'product_assets.report_id', '=', 'reports.id')->select(
            DB::raw('
                CONCAT("[", group_concat(substring(product_assets.resources, 2, length(product_assets.resources) - 2)), "]") AS json
            ')
        );
}

结果：

"meanings": [
    "[
    {\"name\": \"Product 1\", \"product_id\": \"1\", \"quantity\": 4},
    {\"name\": \"Product 1\", \"product_id\": \"1\", \"quantity\": 1},
    {\"name\": \"Product 1\", \"product_id\": \"1\", \"quantity\": 1},
    {\"name\": \"Product 1\", \"product_id\": \"1\", \"quantity\": 4},
    {\"name\": \"Product 2\", \"product_id\": \"2\", \"quantity\": 4},
    {\"name\": \"Product 3\", \"product_id\": \"3\", \"quantity\": 4},
    {\"na]"
]

因此基本上，它应该搜索具有相同product_id的对象，如果有多个具有相同product_id的对象，则应求和将所有具有相同product_id的对象归为一，因此结果应类似于以下内容：

预期结果：

"meanings": [
    "[
    {\"name\": \"Product 1\", \"product_id\": \"1\", \"quantity\": 10},
    {\"name\": \"Product 2\", \"product_id\": \"2\", \"quantity\": 4},
    {\"name\": \"Product 3\", \"product_id\": \"3\", \"quantity\": 4},
    {\"na]"
]

这甚至可能吗，我怎么能做到这一点，我刚开始使用mysql json，但我不知道。谢谢。

Answer 1

您需要解码json，然后计算具有相同ID的产品数量，然后将其编码回来。

$data = [];
$pId = [];
$objects = $this->reports()->getBasicMeans($this->id)->get();
foreach($objects as $object)
{
    $newData = json_decode($object);
    $data[$newData->product_id]['name'] = $newData->name;
    $data[$newData->product_id]['product_id'] = $newData->product_id;
    if (!in_array($newData->product_id, $pId)) {
        $pId[] = $newData->product_id;
        $data[$newData->product_id]['quantity'] = $newData->quantity;
    } else {
        $data[$newData->product_id]['quantity'] += $newData->quantity;
    }
}

$json['meanings'] = json_encode($data);

这可以帮助您实现所需的目标。

用php和mysql求和json数量

1 个答案: