Question

预期结果为3201：20。我已经用“：”分割了。请提出实现此目标的最佳方法。

DECLARE @tmpTime TABLE
(
    RowId INT IDENTITY(1, 1),
    EmployeeId INT,
    TotalWorkingTime NVARCHAR(10)
);

INSERT INTO @tmpTime
(
    EmployeeId, TotalWorkingTime
)
VALUES
(1,N'1500:30'),
(2,N'1700:50');

SELECT SUM(TotalWorkingTime) FROM @tmpTime

Answer 1

SQL Server不会关闭超过24小时的时间类型。因此，不要以time的方式考虑您的工作。它只是数字的时髦字符串表示形式。

因此，您可以将值解析为数字，进行求和，然后重建值：

select (cast(sum(hh) + sum(mm) / 60 as varchar(255)) + ':' +
        right('00' + cast(sum(mm) % 60 as varchar(255)), 2)
       ) as hhmm
from ( VALUES (1,N'1500:30'), (2,N'1700:50') ) t(EmployeeId, TotalWorkingTime) cross apply
     (values (cast(left(TotalWorkingTime, charindex(':', TotalWorkingTime) - 1) as int),
              cast(stuff(TotalWorkingTime, 1, charindex(':', TotalWorkingTime), '') as int)
             )
     ) v(hh, mm)

Answer 2

从@GordonLinoff的答案可以看出，使用VARCHAR表示真正的持续时间时，查询非常复杂。如果您以更自然的方式表示数据，则查询会变得更加简单。例如，如果您将工作时间存储为整数（总分钟），则可以使用中间CTE和几个CROSS APPLY来获得所需的内容：

-- note that TotalWorkingTime is now TotalWorkingTimeMinutes
DECLARE @tmpTime TABLE
(
    RowID INT IDENTITY(1,1),
    EmployeeID INT,
    TotalWorkingTimeMinutes INT
);

-- while I'm using a calculation to show
-- how the minutes get added, this would likely
-- be  done by the application, before it gets
-- sent to the database.
INSERT INTO @tmpTime
(EmployeeID, TotalWorkingTimeMinutes)
VALUES
(1, (1500 * 60) + 30),
(2, (1700 * 60) + 50);

-- I think this intermediate CTE makes things a bit clearer.
-- but of course, you can inline it as well.
WITH SummedMinutesWorked(SummedMinutes) AS
(
    SELECT SUM(TotalWorkingTimeMinutes)
    FROM @tmpTime
)

-- you can use the CROSS APPLY to get the hours,
-- then reference those to get the "remainder minutes"
-- the SELECT has to cast your hours and minutes to a VARCHAR
-- for concatenation
SELECT CAST(H AS VARCHAR(255)) + ':' + CAST(M AS VARCHAR(255))
FROM SummedMinutesWorked
    CROSS APPLY (SELECT SummedMinutes / 60 AS H) AS HoursWorked
    CROSS APPLY (SELECT SummedMinutes - (H * 60) AS M) AS RemainderMinutes

Answer 3

您可以尝试使用left（）和right（）函数在'：'之前和之后查找字符

select 
 concat
 (
  sum(cast(left(TotalWorkingTime,CHARINDEX(':',TotalWorkingTime)-1) as int)),
  ':',
  case when sum(cast(right(TotalWorkingTime,CHARINDEX(':',TotalWorkingTime)-3) as int))>60 then sum(cast(right(TotalWorkingTime,CHARINDEX(':',TotalWorkingTime)-3) as int))-60 else sum(cast(right(TotalWorkingTime,CHARINDEX(':',TotalWorkingTime)-3) as int)) end
 ) FROM @tmpTime

从sql列计算总工作时间

3 个答案: