Question

我试图找到两个数字的百分比差异。实际情况是iam获取本周和上周的用户数据总值。现在，我需要查看本周数据和上周数据的性能差异百分比。以下是我正在尝试的代码。但是有时任何一个数据都将为零，并且会出现错误“被零除”。如何处理？

$this_week_cust=$row["cust_count_new"];
$last_week_cust=$row["cust_count_old"];

$percentChange = (1 - $last_week_cust / $this_week_cust) * 100;

Answer 1

您可以检查$this_week_cust是否为零，只需将更改设置为100％

$this_week_cust=$row["cust_count_new"];
$last_week_cust=$row["cust_count_old"];
if ( $this_week_cust == 0 ) {
   $percentChange = -100;
}
else {
   $percentChange = (1 - $last_week_cust / $this_week_cust) * 100;
}

如果$last_week_cust也为0，那么更改将为0，所以也许

if ( $this_week_cust == 0 ) {
   $percentChange = ($last_week_cust==0)?0:-100;
}

Answer 2

尝试

如果$this_week_cust!=0仅执行该时间计算，否则将不执行任何操作

$this_week_cust=$row["cust_count_new"];
$last_week_cust=$row["cust_count_old"];
if($this_week_cust!=0){
   $percentChange = (1 - $last_week_cust / $this_week_cust) * 100;
}

Answer 3

您可以通过检查$this_week_cust来获得所需的结果，如果它返回零，为null或为空，则将$ this_week_cust设置为100；

$percentChange=100;

Answer 4

我认为这会对您有所帮助。

$original= 1000;
$current = 5;
$diff = $current - $original;
$more_less = $diff > 0 ? "More" : "Less";
$diff = abs($diff);
$percentChange = ($diff/$original)*100;
echo "$percentChange% $more_less agaist $original";

PHP计算两个数字之间的百分比差异

4 个答案: