Question

我有一个代码询问用户是否要玩游戏，请按Y或N。如果按Y，则要求他们在1到10之间选择一个数字，如果按N，则说好。

但是我要它再次询问用户输入的不是y还是n。如果他们不按y或n，它将一再询问直到他们按y或n。

#!/usr/bin/env python3

import random

number = random.randint(1, 10)
tries = 0
win = False # setting a win flag to false


name = input("Hello, What is your username?")

print("Hello" + name + "." )


question = input("Would you like to play a game? [Y/N] ")
if question.lower() == "n": #in case of capital letters is entered
    print("oh..okay")
    exit()
if question.lower() == "y":
    print("I'm thinking of a number between 1 & 10")


while not win:  # while the win is not true, run the while loop. We set win to false at the start therefore this will always run
    guess = int(input("Have a guess: "))
    tries = tries + 1
    if guess == number:
        win = True    # set win to true when the user guesses correctly.
    elif guess < number:
        print("Guess Higher")
    elif guess > number:
        print("Guess Lower")
# if win is true then output message
print("Congrats, you guessed correctly. The number was indeed {}".format(number))
print("it had taken you {} tries".format(tries))

Answer 1

添加一个while循环以确保他们选择其中之一：

[..]
question = ''
while question.lower() not in ['n', 'y']:
    question = input("Would you like to play a game? [Y/N] ")

if question.lower() == "n": #in case of capital letters is entered
    print("oh..okay")
    exit()

# No need of else or elif here because 'n' answers will exit code.
print("I'm thinking of a number between 1 & 10")

[..]

Answer 2

尝试将您的问题代码放入函数中。像这样：

def ask():
    question = input("Would you like to play a game? [Y/N] ")
    if question.lower() == "n": #in case of capital letters is entered
        print("oh..okay")
        exit()
    elif question.lower() == "y":
        print("I'm thinking of a number between 1 & 10")
    else:
        ask()

要求正确的输入，直到在python中给出

2 个答案: