python循环request.get()仅返回第一个循环

时间:2018-10-31 22:07:20

标签: python python-3.x loops python-requests

尝试从多个网页中抓取表格并将其存储在列表中。该列表将第一个网页的结果打印3次。

import pandas as pd
import requests
from bs4 import BeautifulSoup

dflist = []
for i in range(1,4):
    s = requests.Session()
    res = requests.get(r'http://www.ironman.com/triathlon/events/americas/ironman/world-championship/results.aspx?p=' + str(i) + 'race=worldchampionship&rd=20181013&agegroup=Pro&sex=M&y=2018&ps=20#axzz5VRWzxmt3')
    soup = BeautifulSoup(res.content,'lxml')
    table = soup.find_all('table')
    dfs = pd.read_html(str(table))
    dflist.append(dfs)
    s.close()

print(dflist)  

1 个答案:

答案 0 :(得分:2)

您在&之后遗漏了'?p=' + str(i),因此您的所有请求都将p设置为${NUMBER}race=worldchampionship,ironman.com可能没有任何意义,只是忽略。在&的开头插入'race=worldchampionship'

为防止将来发生此类错误,您可以将URL的查询参数作为dict传递给params关键字参数,如下所示:

    params = {
        "p": i,
        "race": "worldchampionship",
        "rd": "20181013", 
        "agegroup": "Pro",
        "sex": "M",
        "y": "2018",
        "ps": "20",
    }

    res = requests.get(r'http://www.ironman.com/triathlon/events/americas/ironman/world-championship/results.aspx#axzz5VRWzxmt3', params=params)