android从图库中选择图像

时间：2011-03-15 08:33:47

标签： android gallery action

我想从图库中创建一个图片选择器。我用代码

 intent = new Intent(Intent.ACTION_PICK, android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
 startActivityForResult(intent, TFRequestCodes.GALLERY);

我的问题是在此活动中显示视频文件。有没有办法过滤显示的文件，以便在此活动中不显示任何视频文件？

16 个答案:

答案 0 :(得分：303)

绝对。试试这个：

Intent intent = new Intent();
intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent, "Select Picture"), PICK_IMAGE);

不要忘记创建常量 PICK_IMAGE ，这样您就可以识别用户何时从图库中回来活动：

public static final int PICK_IMAGE = 1;

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data)
{
    if (requestCode == PICK_IMAGE) {
        //TODO: action
    }
}

这就是我调用图片库的方式。把它放进去看看它是否适合你。

编辑：

这会打开Documents应用程序。要允许用户也使用他们可能已安装的任何图库应用程序：

    Intent getIntent = new Intent(Intent.ACTION_GET_CONTENT);
    getIntent.setType("image/*");

    Intent pickIntent = new Intent(Intent.ACTION_PICK, android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
    pickIntent.setType("image/*");

    Intent chooserIntent = Intent.createChooser(getIntent, "Select Image");
    chooserIntent.putExtra(Intent.EXTRA_INITIAL_INTENTS, new Intent[] {pickIntent});

    startActivityForResult(chooserIntent, PICK_IMAGE);

答案 1 :(得分：184)

有时，您无法从您选择的图片中获取文件。 这是因为选择的人来自Google+，云端硬盘，Dropbox或任何其他提供商。

最佳解决方案是让系统通过Intent.ACTION_GET_CONTENT选择内容，并通过内容提供商获取结果。

您可以按照下面的代码或查看我的updated gist。

public void pickImage() {
  Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
  intent.setType("image/*");
  startActivityForResult(intent, PICK_PHOTO_FOR_AVATAR);
}

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == PICK_PHOTO_FOR_AVATAR && resultCode == Activity.RESULT_OK) {
        if (data == null) {
            //Display an error
            return;
        }
        InputStream inputStream = context.getContentResolver().openInputStream(data.getData());
        //Now you can do whatever you want with your inpustream, save it as file, upload to a server, decode a bitmap...
    }
}

答案 2 :(得分：24)

public void FromCamera() {

    Log.i("camera", "startCameraActivity()");
    File file = new File(path);
    Uri outputFileUri = Uri.fromFile(file);
    Intent intent = new Intent(
            android.provider.MediaStore.ACTION_IMAGE_CAPTURE);
    intent.putExtra(MediaStore.EXTRA_OUTPUT, outputFileUri);
    startActivityForResult(intent, 1);

}

public void FromCard() {
    Intent i = new Intent(Intent.ACTION_PICK,
            android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
    startActivityForResult(i, 2);
}

 protected void onActivityResult(int requestCode, int resultCode, Intent data) {

    super.onActivityResult(requestCode, resultCode, data);

    if (requestCode == 2 && resultCode == RESULT_OK
            && null != data) {

        Uri selectedImage = data.getData();
        String[] filePathColumn = { MediaStore.Images.Media.DATA };

        Cursor cursor = getContentResolver().query(selectedImage,
                filePathColumn, null, null, null);
        cursor.moveToFirst();

        int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
        String picturePath = cursor.getString(columnIndex);
        cursor.close();

        bitmap = BitmapFactory.decodeFile(picturePath);
        image.setImageBitmap(bitmap);

        if (bitmap != null) {
            ImageView rotate = (ImageView) findViewById(R.id.rotate);

        }

    } else {

        Log.i("SonaSys", "resultCode: " + resultCode);
        switch (resultCode) {
        case 0:
            Log.i("SonaSys", "User cancelled");
            break;
        case -1:
            onPhotoTaken();
            break;

        }

    }

}

protected void onPhotoTaken() {
    // Log message
    Log.i("SonaSys", "onPhotoTaken");
    taken = true;
    imgCapFlag = true;
    BitmapFactory.Options options = new BitmapFactory.Options();
    options.inSampleSize = 4;
    bitmap = BitmapFactory.decodeFile(path, options);
    image.setImageBitmap(bitmap);


}

答案 3 :(得分：19)

您可以使用此方法从图库中选择图像。只显示图像。

public void pickImage() {
    Intent intent = new Intent(Intent.ACTION_PICK,
            MediaStore.Images.Media.INTERNAL_CONTENT_URI);
    intent.setType("image/*");
    intent.putExtra("crop", "true");
    intent.putExtra("scale", true);
    intent.putExtra("outputX", 256);
    intent.putExtra("outputY", 256);
    intent.putExtra("aspectX", 1);
    intent.putExtra("aspectY", 1);
    intent.putExtra("return-data", true);
    startActivityForResult(intent, 1);
}

并将onActivityResult覆盖为

    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        if (resultCode != RESULT_OK) {
            return;
        }
        if (requestCode == 1) {
            final Bundle extras = data.getExtras();
            if (extras != null) {
                //Get image
                Bitmap newProfilePic = extras.getParcelable("data");
            }
        }
    }

答案 4 :(得分：8)

这里是请求权限的完整示例（如果需要），从图库中选择图片，然后将图片转换为bitmap或file

AndroidManifesh.xml 

<uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE"/>

活动 

class MainActivity : AppCompatActivity() {

    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        setContentView(R.layout.activity_main)

        button_pick_image.setOnClickListener {
            pickImage()
        }
    }

    private fun pickImage() {
        if (ActivityCompat.checkSelfPermission(this, READ_EXTERNAL_STORAGE) == PackageManager.PERMISSION_GRANTED) {
            val intent = Intent(
                Intent.ACTION_PICK,
                MediaStore.Images.Media.INTERNAL_CONTENT_URI
            )
            intent.type = "image/*"
            intent.putExtra("crop", "true")
            intent.putExtra("scale", true)
            intent.putExtra("aspectX", 16)
            intent.putExtra("aspectY", 9)
            startActivityForResult(intent, PICK_IMAGE_REQUEST_CODE)
        } else {
            ActivityCompat.requestPermissions(
                this,
                arrayOf(Manifest.permission.READ_EXTERNAL_STORAGE),
                READ_EXTERNAL_STORAGE_REQUEST_CODE
            )
        }
    }

    override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
        super.onActivityResult(requestCode, resultCode, data)
        if (requestCode == PICK_IMAGE_REQUEST_CODE) {
            if (resultCode != Activity.RESULT_OK) {
                return
            }
            val uri = data?.data
            if (uri != null) {
                val imageFile = uriToImageFile(uri)
                // todo do something with file
            }
            if (uri != null) {
                val imageBitmap = uriToBitmap(uri)
                // todo do something with bitmap
            }
        }
    }

    override fun onRequestPermissionsResult(requestCode: Int, permissions: Array<out String>, grantResults: IntArray) {
        super.onRequestPermissionsResult(requestCode, permissions, grantResults)
        when (requestCode) {
            READ_EXTERNAL_STORAGE_REQUEST_CODE -> {
                if (grantResults[0] == PackageManager.PERMISSION_GRANTED) {
                    // pick image after request permission success
                    pickImage()
                }
            }
        }
    }

    private fun uriToImageFile(uri: Uri): File? {
        val filePathColumn = arrayOf(MediaStore.Images.Media.DATA)
        val cursor = contentResolver.query(uri, filePathColumn, null, null, null)
        if (cursor != null) {
            if (cursor.moveToFirst()) {
                val columnIndex = cursor.getColumnIndex(filePathColumn[0])
                val filePath = cursor.getString(columnIndex)
                cursor.close()
                return File(filePath)
            }
            cursor.close()
        }
        return null
    }

    private fun uriToBitmap(uri: Uri): Bitmap {
        return MediaStore.Images.Media.getBitmap(this.contentResolver, uri)
    }

    companion object {
        const val PICK_IMAGE_REQUEST_CODE = 1000
        const val READ_EXTERNAL_STORAGE_REQUEST_CODE = 1001
    }
}

演示
https://github.com/PhanVanLinh/AndroidPickImage

答案 5 :(得分：5)

仅根据文档为API最低19岁的用户提供答案的更新：

在Android 4.4（API级别19）及更高版本上，您还可以使用ACTION_OPEN_DOCUMENT意向，该附加意向可显示系统控制的选择器UI，该用户界面受控制，允许用户浏览其他应用程序提供的所有文件。用户可以通过单个UI从任何受支持的应用中选择文件。

在Android 5.0（API级别21）及更高版本上，您还可以使用ACTION_OPEN_DOCUMENT_TREE意图，该意图使用户可以选择客户端应用访问的目录。

Open files using storage access framework - Android Docs 

     val intent = Intent(Intent.ACTION_OPEN_DOCUMENT)
     intent.type = "image/*"
     startActivityForResult(intent, PICK_IMAGE_REQUEST_CODE)

答案 6 :(得分：5)

我有同样的问题。我使用此代码

addIntent 

 Intent intent = new Intent();
        intent.setType("image/*");
        intent.setAction(Intent.ACTION_GET_CONTENT);
        startActivityForResult(Intent.createChooser(intent, "Tack Image"), PICK_PHOTO);

添加 onActivityResult 

 @Override
  public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == PICK_PHOTO && resultCode == Activity.RESULT_OK) {
      if (data == null) {
      //error
        return;
      }
      try {
        Uri uri = data.getData();
        File file = FileUtil.from(currentActivity, uri);
      } catch (IOException e) {
        e.printStackTrace();
      }
    }
  }

FileUtil类 

import android.content.Context;
import android.database.Cursor;
import android.net.Uri;
import android.provider.OpenableColumns;
import android.util.Log;

import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;

public class FileUtil {
  private static final int EOF = -1;
  private static final int DEFAULT_BUFFER_SIZE = 1024 * 4;

  private FileUtil() {

  }

  public static File from(Context context, Uri uri) throws IOException {
    InputStream inputStream = context.getContentResolver().openInputStream(uri);
    String fileName = getFileName(context, uri);
    String[] splitName = splitFileName(fileName);
    File tempFile = File.createTempFile(splitName[0], splitName[1]);
    tempFile = rename(tempFile, fileName);
    tempFile.deleteOnExit();
    FileOutputStream out = null;
    try {
      out = new FileOutputStream(tempFile);
    } catch (FileNotFoundException e) {
      e.printStackTrace();
    }
    if (inputStream != null) {
      copy(inputStream, out);
      inputStream.close();
    }

    if (out != null) {
      out.close();
    }
    return tempFile;
  }

  private static String[] splitFileName(String fileName) {
    String name = fileName;
    String extension = "";
    int i = fileName.lastIndexOf(".");
    if (i != -1) {
      name = fileName.substring(0, i);
      extension = fileName.substring(i);
    }

    return new String[]{name, extension};
  }

  private static String getFileName(Context context, Uri uri) {
    String result = null;
    if (uri.getScheme().equals("content")) {
      Cursor cursor = context.getContentResolver().query(uri, null, null, null, null);
      try {
        if (cursor != null && cursor.moveToFirst()) {
          result = cursor.getString(cursor.getColumnIndex(OpenableColumns.DISPLAY_NAME));
        }
      } catch (Exception e) {
        e.printStackTrace();
      } finally {
        if (cursor != null) {
          cursor.close();
        }
      }
    }
    if (result == null) {
      result = uri.getPath();
      int cut = result.lastIndexOf(File.separator);
      if (cut != -1) {
        result = result.substring(cut + 1);
      }
    }
    return result;
  }

  private static File rename(File file, String newName) {
    File newFile = new File(file.getParent(), newName);
    if (!newFile.equals(file)) {
      if (newFile.exists() && newFile.delete()) {
        Log.d("FileUtil", "Delete old " + newName + " file");
      }
      if (file.renameTo(newFile)) {
        Log.d("FileUtil", "Rename file to " + newName);
      }
    }
    return newFile;
  }

  private static long copy(InputStream input, OutputStream output) throws IOException {
    long count = 0;
    int n;
    byte[] buffer = new byte[DEFAULT_BUFFER_SIZE];
    while (EOF != (n = input.read(buffer))) {
      output.write(buffer, 0, n);
      count += n;
    }
    return count;
  }
}

，您必须将 provider_paths.xml 添加到xml文件夹（如image） enter image description here

provider_paths.xml 

<?xml version="1.0" encoding="utf-8"?>
<paths>
    <external-path name="external_files" path="."/>
</paths>

最后在 AndroidManifest.xml

中添加以下内容 
<application
...>

...
      <provider
          android:name="androidx.core.content.FileProvider"
          android:authorities="${applicationId}.provider"
          android:exported="false"
          android:grantUriPermissions="true">
          <meta-data
            android:name="android.support.FILE_PROVIDER_PATHS"
            android:resource="@xml/provider_paths" />
        </provider>
...
</application>

希望我能帮助

答案 7 :(得分：3)

再见 startActivityForResult()

现在使用 AndroidX Activity 的正确方法是 Activity Result API，google 强烈推荐这种方法

private val selectImageFromGalleryResult = registerForActivityResult(ActivityResultContracts.GetContent()) { uri: Uri? ->
    uri?.let { previewImage.setImageURI(uri) }
}

只需在需要时调用 selectImageFromGallery()

private fun selectImageFromGallery() = selectImageFromGalleryResult.launch("image/*")

答案 8 :(得分：2)

如果您只是寻找图像和多种选择。

看看@ https://stackoverflow.com/a/15029515/1136023

这对未来很有帮助。我个人感觉很棒，使用MultipleImagePick。

答案 9 :(得分：2)

2021 Kotlin 解决方案与新版本的 Fragment：

dependencies {
  implementation "androidx.fragment:fragment:1.3.3"
}

class YourFragment : Fragment() {

    private val fileChooserContract = registerForActivityResult(ActivityResultContracts.GetContent()) { imageUri ->
        if (imageUri != null) {
            // imageUri now contains URI to selected image
        }
    }

    // ...

    fun openFileChooser() {
        fileChooserContract.launch("image/*")
    }
}

答案 10 :(得分：0)

仅从本地选择，请添加以下内容： 

        i.putExtra(Intent.EXTRA_LOCAL_ONLY,true)

这很好用：

    val i = Intent(Intent.ACTION_GET_CONTENT,MediaStore.Images.Media.EXTERNAL_CONTENT_URI)
    i.type = "image/*"
    i.putExtra(Intent.EXTRA_LOCAL_ONLY,true)
    startActivityForResult(Intent.createChooser(i,"Select Photo"),pickImageRequestCode)

答案 11 :(得分：0)

OPTION-1

以下代码允许用户从任何文件资源管理器应用程序中选择图像

Intent intent = new Intent();
intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent, "Select Picture"), PICK_IMAGE_CODE);

但在某些设备中，上述解决方案将无法获取带有方向等 EXIF 信息的图像。因此，在这些设备中，无法按预期执行更改图像方向等 EXIF 处理。

OPTION-2

以下代码允许用户从任何图库应用程序中选择图像

Intent intent = new Intent(Intent.ACTION_PICK, MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
intent.setType("image/*");
startActivityForResult ( intent, PICK_IMAGE_CODE );

但在某些设备中，在设置意图类型时，上述解决方案会清除意图数据（MediaStore.Images.Media.EXTERNAL_CONTENT_URI），这可能会阻碍图库的打开过程。

OPTION-3

最后，我建议使用下面的代码，它允许用户从任何图库应用程序中选择一个不会导致任何问题且不显示任何警告的图像

Intent intent = new Intent ();
intent.setAction ( Intent.ACTION_PICK );
intent.setDataAndType ( MediaStore.Images.Media.EXTERNAL_CONTENT_URI, "image/*" );
startActivityForResult ( intent, PICK_IMAGE_CODE );

答案 12 :(得分：0)

Kotlin：当您想提示用户时打开 ACTION_GET_CONTENT 事件：

val intent = Intent(Intent.ACTION_GET_CONTENT).apply { type = "image/*" }
startActivityForResult(intent, 9998)

在用户选择图像后，在您的 Activity 的 onActivityResult 函数中处理该事件。例如，我将其显示在 ImageView 中并将其存储在应用缓存中：

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
    super.onActivityResult(requestCode, resultCode, data)
    if (requestCode == 9998) {
        val uri: Uri = data?.data ?: return
        val bytes = contentResolver.openInputStream(uri)?.readBytes() ?: return
        imageView.setImageBitmap(BitmapFactory.decodeByteArray(bytes, 0, bytes.size))
        File("$cacheDir/imgPicked").writeBytes(bytes)  // if needed: store to cache
    }
}

理想情况下，将 9998 替换为您的应用使用的一些内部请求代码枚举。这只是为了将回调与您自己的请求区分开来。

与 getParcelable("data") 不同，这不需要任何权限。

请注意，这不会处理设置它的图像上的 Exif rotation bit，因此一些图像最终会出现不正确的方向 (Kotlin solution)。

答案 13 :(得分：0)

感谢 mklkj。

这是一个活动版本。

fileChooserContract 可以选择图像。 filesChooserContract 可以选择多张图片。

class MainActivity : AppCompatActivity() {

    companion object {
        private const val TAG = "MainActivity"
    }

    lateinit var viewBinding: ActivityMainBinding

    private val fileChooserContract = registerForActivityResult(ActivityResultContracts.GetContent()) { uri ->
        Log.d(TAG, "onActivityResult: uri $uri")
    }

    private val filesChooserContract = registerForActivityResult(ActivityResultContracts.GetMultipleContents()) { uriList ->
        for (uri in uriList) {
            Log.d(TAG, "onActivityResult: uri $uri")
        }
    }

    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        viewBinding = ActivityMainBinding.inflate(layoutInflater)
        setContentView(viewBinding.root)

        viewBinding.btnPick.setOnClickListener {
            fileChooserContract.launch("image/*")
        }

        viewBinding.btnPickMulti.setOnClickListener {
            filesChooserContract.launch("image/*")
        }
    }
}

答案 14 :(得分：0)

以下是 kotlin 中的 util 方法的工作代码：

fun launchGalleryWithFragment() {
        val intent = Intent(Intent.ACTION_PICK, MediaStore.Images.Media.EXTERNAL_CONTENT_URI)
        intent.type = "image/*"
        startActivityForResult(Intent.createChooser(intent, "Select Picture"), 1001)
    }

现在覆盖 onActivityResult 方法：

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
    super.onActivityResult(requestCode, resultCode, data)
var path: Uri? = null
        if (requestCode == PICK_IMAGE_REQUEST && resultCode == Activity.RESULT_OK) {
            if(dataIntent == null || dataIntent.data == null){
                return null
            }
            path = dataIntent.data
        }

}

答案 15 :(得分：-5)

你可以比这个答案更容易做到：

Uri Selected_Image_Uri = data.getData();
ImageView imageView = (ImageView) findViewById(R.id.loadedimg);
imageView.setImageURI(Selected_Image_Uri);
相关问题
最新问题