为什么我的打印功能用下面的代码中的最后一个条目覆盖以前的条目?

时间:2018-10-31 17:51:17

标签: c hashtable

这是一个简单程序的开始,该程序将用户条目存储在哈希表中。它仍然是非常基本的(还没有添加链接列表来处理冲突,哈希函数非常简单,是更强大的临时占位符,我还没有处理释放所有malloc的内存,等等),但是我想先了解一下基本功能,然后再继续。

在此版本中,我的最新条目似乎覆盖了以前的条目。看起来这些条目仍在正确的位置(由哈希函数决定),但是不知何故,最后一个是放置在各处的条目。

对不起,我知道很多代码,但是我不确定如何创建此代码的较小版本来隔离问题:

exports.encomenda_create = function (req, res, next) {

我确定此代码还有其他问题,我很感谢任何人愿意在此处提供的其他建议。例如,我总是想知道代码的哪些部分需要自己的功能,哪些应该/可以组合在一起。似乎其中的一些内容应该分开,但是在弄清楚如何正确地将信息从一个函数传递给另一个函数时,我遇到了很多麻烦。

更新#1 (在一些评论之后):

是的,现在可以使用!

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

#define BUF_SIZE_WORDS 4096
#define BUF_SIZE_NUMBERS 256
#define MAX_WORDS 10

typedef struct tablestruct
{
    int val;
    char* text;
    struct tablestruct *next;
}
table;


// declare the hashing function that takes in the string to be hashed and the length of it
unsigned int hash(char *str, int length);

// // declare a linked list creation function
// lnode *createnode(char *str, htnode *hashtable);

// declare a hash table printing function
void print_ht(table *array[MAX_WORDS]);


int number_input();
int word_input(int num_words, table *array[MAX_WORDS]);
void empty_stdin();

int main(void)
{
    // call number_input() to ask user for number of words they'd like to store, save that in word_count
    int word_count = number_input();

    // create hash table
    table *array[MAX_WORDS];

    for (int j = 0; j < MAX_WORDS; j++)
    {
        array[j] = malloc(sizeof(table));
        array[j]->val = j;
    }

    // add some kind of a memory check?

    // PUT word_input inside the if statement to make sure it worked?
    // call word_input() and store the result in success
    int success = word_input(word_count, array);
    // if not successful:
    if (!success)
    {
        fputs ("some kind of problem with word_input\n", stderr);
        return 1;
    }

    // printf("\ncurrent address of the hash table: %p\n", &array[0]);

    printf("printing hash table: \n");

    print_ht(array);

    // REMEMBER TO FREE WHATEVER'S MALLOC'ED
}

int number_input(void)
{
    // a bunch of code is borrowed from David's answer here: https://stackoverflow.com/questions/52920852/why-is-the-following-code-not-allowing-me-to-get-user-input-with-fgets-yet-works?noredirect=1#comment92940817_52920852

    int num_words = 0,       /* number of words to enter */
        word_count_check = 0;          /* word count */

    char buffer[BUF_SIZE_NUMBERS] = "";    /* buffer of sufficient size for input */

    for (;;) /* loop continually until valid input of NUMBER OF WORDS USER WANTS TO ENTER or user cancels */
    {
        printf ("how many words would you like to enter? [1-%d]: ", MAX_WORDS);
        // check for cancellation of input
        if (!fgets (buffer, BUF_SIZE_NUMBERS, stdin))
        {
            fputs ("user canceled input\n", stderr);
            return 1;
        }

        // check if user simply hit enter w/o typing anything
        if(buffer[0] == '\n')
        {
            printf("please enter a value\n");
            continue;
        }

        size_t inlength = strlen(buffer);

        if (inlength && buffer[inlength - 1] == '\n')
        {
            // printf("hurray!\n");
            buffer[--inlength] = 0;
        }
        else if (inlength == BUF_SIZE_NUMBERS - 1) /* the line was too long */
        {
            printf("you've entered too many characters... please stick to a maximum of %i\n", BUF_SIZE_NUMBERS);
            empty_stdin();
            // continue;
        }

        // make sure user actually entered a proper int
        if (sscanf (buffer, "%d", &num_words) != 1) /* sscanf is used for conversion */
        {
            fputs ("invalid conversion to int; please provide valid input\n", stderr);
            continue;
        }

        // check if the number entered is out of range
        if (num_words < 1 || num_words > MAX_WORDS)
            fprintf (stderr, "%2d out of valid range.\n", num_words);
        else
            break; /*if the input has been validated, we can now break out of the for loop */
    }

    return(num_words);
}

int word_input(int num_words, table *array[MAX_WORDS])
{
    int word_count = 0;

    for(;;) /* loop until word_count == num_words is achieved */
    {
        // declare an array for storing input string
        char buffer[BUF_SIZE_WORDS];
        char valid_input[BUF_SIZE_WORDS];

        // prompt user for input
        printf("\nplease enter a string: ");

        // get input and check for CTRL+D
        if (!fgets(buffer, BUF_SIZE_WORDS, stdin))
        {
            fputs ("user canceled input\n", stderr);
            exit(1);
        }

         // check if user simply hit enter w/o typing anything
        if(buffer[0] == '\n')
        {
            printf("please enter a word that's more than 0 characters\n");
            // empty_stdin();
            continue;
        }

        size_t inlength = strlen(buffer);

        if (inlength && buffer[inlength - 1] == '\n')
        {
            buffer[--inlength] = 0;

            // get rid of trailing spaces using sscanf
            sscanf(buffer, "%s", valid_input);
            inlength = strlen(valid_input);

            printf("string length: %zu\n", inlength);

            // call the hash function to get the hash code
            int result = hash(&valid_input[0], inlength);

            table *newnode = malloc(sizeof(table));

            // store the current string in the newnode->text
            newnode->text = valid_input;
            // strcpy(newnode->text, valid_input); ??
            // newnode->val = inlength;

            // confirm string has been stored
            printf("you've entered: %s\n", newnode->text);

            // attach the node to correct slot in the hash table -- ADD LINKED LIST FUNCTIONALITY HERE TO DEAL WITH COLLISIONS!
            array[result]->next = newnode;
            // printf("address of the current HT entry is: %p\n", newnode);

            // increment word count
            word_count++;
            printf("word_count = %i\n", word_count);

            if (word_count == num_words)
            {
                 printf("\nDONE!\n\n");
                 return word_count;
            }
        }
        // check if the user entered too many characters
        else if (inlength == BUF_SIZE_WORDS - 1) /* the line was too long */
        {
            printf("you've entered too many characters... please stick to a maximum of %i\n", BUF_SIZE_WORDS);
            empty_stdin();
        }
    }
    // return word_count;
}


/* helper function to remove any chars left in input buffer */
void empty_stdin()
{
    int c = getchar();
    while (c != '\n' && c != EOF)
        c = getchar();
}

// THIS HASH FUNCTION IS TOO BASIC AND NEEDS TO BE REPLACED WITH SOMETHING BETTER
unsigned int hash(char *str, int length)
{
    int sum = 0;
    for (int j = 0; j < length; j++)
    {
        sum += str[j];
    }
    printf("here's what the hashing function is returning: %i\n", (sum % MAX_WORDS));
    return sum % MAX_WORDS;
}

void print_ht(table *array[MAX_WORDS])
{
    // printf("address of the hash table inside print function: %p\n\n", array);

    table *cursor = malloc(sizeof(table));
    // add memory check

    for (int i = 0; i < MAX_WORDS; i++)
    {
        printf("[%i] -> ", i);
        cursor = array[i];
        if (cursor->next)
        {
            table *temp = malloc(sizeof(table));
            temp = cursor->next;

            printf("%s\n", temp->text);
            free(temp);
        }
        else
        {
            printf("empty\n");
        }
    }
    free(cursor);
}

1 个答案:

答案 0 :(得分:1)

您正在为每个节点设置newnode->text = valid_input;。但是valid_input是在word_input的for循环范围内声明的本地缓冲区。因此,这不是有效的代码-不能保证该函数之外还存在缓冲区。

实际上,valid_input包含一些堆栈存储器的地址,每次进入此函数时都会重复使用该地址,因此所有node->text指针最终都指向包含最后一个值的同一存储器输入。

通过打印所有节点的文本指针的值,您应该能够验证这种情况。

您需要为要保存的每个条目创建一个新缓冲区。