Question

我需要在其中创建一个临时文件：

Partcode，MutationDate，MovementType，数量

每个移动代码的每个部件代码都有多个突变日期（最多可以有9个移动类型）我需要获取每个零件代码每个运动类型的最后突变日期以及随之而来的数量。

零件代码为003307的示例

003307 2018-05-31 1 -100
003307 2018-06-11 2 -33
003307 2018-04-25 3 +25

所有9种运动类型的依此类推。

到目前为止，我得到了什么？

create table #LMUT(
    MutationDate T_Date
    ,PartCode T_Code_Part
    ,CumInvQty T_Quantum_Qty10_3
    ,MovementType T_Type_PMOverInvt
    )

    insert #LMUT(
    MutationDate,
    Partcode,
    CumInvQty,
    MovementType)
    SELECT
    cast (max(MOV.MutationDate) as date)
    ,MOV.PartCode
    ,INV.MutationQty
    ,INV.PMOverInvtType
    FROM dbo.T_PartMovementMain as MOV
    inner join dbo.T_PartMovementOverInvt as INV on

INV.PMMainCode=MOV.PMMainCode
        WHERE
        MOV.PartMovementType = 1
        group by MOV.PartCode,INV.PMOverInvtType,INV.MutationQty,MOV.MutationDate

SELECT * FROM #LMUT where partcode='003007'
drop table #LMUT

导致：

    2016-12-06 00:00:00.000 003007 -24.000 2
    2016-09-29 00:00:00.000 003007 -24.000 2
    2016-11-09 00:00:00.000 003007 -24.000 2
    2016-11-22 00:00:00.000 003007 -24.000 2
    2016-10-26 00:00:00.000 003007 -24.000 2
    2016-09-12 00:00:00.000 003007 -42.000 2
    2016-10-13 00:00:00.000 003007 -24.000 2
    2016-12-03 00:00:00.000 003007 100.000 5
    2017-01-12 00:00:00.000 003007 -48.000 2
    2016-10-04 00:00:00.000 003007 306.000 7

不是我所需要的，仍然有8次输入2

我还尝试了什么：

SELECT distinct MOV.Partcode,INV.PMOverInvtType,mov.MutationDate
        FROM dbo.T_PartMovementMain as MOV
        inner join dbo.T_PartMovementOverInvt as INV on
        INV.PMMainCode=MOV.PMMainCode
        WHERE
        mov.MutationDate = (SELECT MAX (c.MutationDate) FROM
        dbo.T_PartMovementMain as c
        inner join dbo.T_PartMovementOverInvt as d on D.PMMainCode=c.PMMainCode
                             WHERE
                                     C.PartMovementType = 1 AND
                                     C.PartCode=mov.PartCode AND
                                     D.PMMainCode = C.PMMainCode AND
                                     D.PMOverInvtType=inv.PMOverInvtType                                     
                                    )        
         and MOV.PartMovementType = 1 and mov.partcode='003007'
        order by MOV.Partcode,INV.PMOverInvtType

结果：

3007    2   2017-01-12 00:00:00.000
3007    5   2016-12-03 00:00:00.000
3007    7   2016-10-04 00:00:00.000

这就是我想要的，但我也需要获取数量。

Answer 1

使用row_number()窗口功能

   with cte as

(         SELECT  MOV.*,INV.*,
          row_number() over(partition by INV.PMOverInvtType order by MOV.MutationDate desc)rn
            FROM dbo.T_PartMovementMain as MOV
            inner join dbo.T_PartMovementOverInvt as INV on
            INV.PMMainCode=MOV.PMMainCode
) select cte.* from cte where rn=1

Answer 2

确定此选择有效，但如何将其整合到我的临时表中

with cte as
(         SELECT  MOV.Partcode,INV.PMOverInvtType,mov.MutationDate,INV.MutationQty,
          row_number() over(partition by MOV.Partcode,INV.PMOverInvtType order by MOV.Partcode,INV.PMOverInvtType,MOV.MutationDate desc) rn
            FROM dbo.T_PartMovementMain as MOV
            inner join dbo.T_PartMovementOverInvt as INV on INV.PMMainCode=MOV.PMMainCode
) 

create table #LMUT(
   PartCode     T_Code_Part
   ,MovementType T_Type_PMOverInvt
   ,MutationDate T_Date 
   ,CumInvQty    T_Quantum_Qty10_3
   )

insert #LMUT(
Partcode,
MovementType,
MutationDate,
CumInvQty)

select cte.* from cte where rn=1

drop table #LMUT

我在#LMUT上遇到创建错误。可能是语法，但我不知道。

Answer 3

像这样解决它：

  create table #LMUT(
   PartCode     T_Code_Part
   ,MovementType T_Type_PMOverInvt
   ,MutationDate T_Date 
   ,CumInvQty    T_Quantum_Qty10_3
   )

insert #LMUT(Partcode,MovementType,MutationDate,CumInvQty)
    select Artikel,Type,Datum,Aant
    from (
        SELECT  MOV.Partcode as Artikel,INV.PMOverInvtType as Type,mov.MutationDate as Datum,INV.MutationQty as Aant,
          row_number() over(partition by MOV.Partcode,INV.PMOverInvtType order by MOV.Partcode,INV.PMOverInvtType,MOV.MutationDate desc) rn
            FROM dbo.T_PartMovementMain as MOV
            inner join dbo.T_PartMovementOverInvt as INV on INV.PMMainCode=MOV.PMMainCode) cse
    where rn=1
select * from #LMUT  order by Partcode  
drop table #LMUT

基于SELECT DISTINCT在3列但有1个额外列的情况下创建温度表

3 个答案: