将基于类的视图转换为“普通”视图

时间:2018-10-31 05:27:05

标签: python django django-rest-framework

我编写了以下django rest框架视图:

# urls.py
url(r'user/company', views.UserViewSet.as_view({"get": "companyInfo"}), name="company_info"),

# views.py
class UserViewSet(viewsets.ModelViewSet):
    serializer_class = UserSerializer
    queryset = User.objects.all()
    permission_classes = (permissions.IsAuthenticated,)

    @action(methods=["get"], detail=True)
    def companyInfo(self, request):
        user = request.user
        company = user.get_company()
        detail = {}
        detail['company'] = company.name
        detail['num_users'] = company.num_licenses if company else None        
        return Response(detail) 

我该如何使用django rest框架编写与“普通” django视图完全相同的视图。例如,如下所示:

# urls.py
path('user/company/', views.company_info, name='company_info'),

# views.py
@require_GET
def company_info(request):
    user = request.user
    company = user.get_company()
    detail = {}
    detail['company'] = company.name
    detail['num_users'] = company.num_licenses if company else None        
    return Response(detail) 

我想以上只是一个开始,但是我认为我仍然需要正确地进行身份验证(使用jwt),UserViewSet会自动对permission_classes = (permissions.IsAuthenticated,)进行认证。

1 个答案:

答案 0 :(得分:0)

您非常接近。您可能想要添加两个装饰器,以使其像在ClassView中一样成为经过身份验证的API视图:

# path('user/company/', views.company_info, name='company_info'),

@api_view(['GET'])
@permission_classes((permissions.IsAuthenticated,))
def company_info(request):
    user = request.user
    company = user.get_company()

    detail = {}
    detail['company'] = company.name
    detail['num_users'] = company.num_licenses if company else None
    detail['company_admin'] = company.admin_user.name if company else None

    return Response(detail)