Question

我想出了一个有用的脚本来帮助监视和控制远程服务器上的服务：

do {
    $srv = Read-Host 'What is your ServerName?'
    $srvs = Read-Host 'What is ServiceName?'
    $userMenuChoice = Read-Host -Prompt "
    `n1. ServiceList
    `n2. Service Status.
    `n3. Stop Service.
    `n4. Start Service.
    `n5. Exit
    `nPlease Select Operation"

    switch($userMenuChoice){
        1{Get-Service -ComputerName $srv | select -property name,starttype}
        2{gsv -cn $srv -Name "$srvs*" | Out-String}
        3{Get-Service -Name "$srvs*" -ComputerName $srv | Stop-Service}
        4{Get-Service -Name "$srvs*" -ComputerName $srv | Start-Service}
        5{exit}
    }
} while ( $userMenuChoice -ne 4 )

请帮我弄清楚如何获得提示，以保持相同的服务器和服务（或不保持）并继续使用相同的菜单。像这样：在进入MENU $ userMenuChoice之前，它将询问我是否要保留相同的服务器Y / N（Y默认）是否要保留相同的服务Y / N（Y Default）...

在继续下一个菜单之前，我如何清除屏幕。谢谢！

Answer 1

这称为Scope。在该区块中创建的Variables仅能在该区块的迭代中幸存。

$A = "Hello"
While(1 -eq 1){
    $B = Read-Host 'Type Name?'
    "$A $B"
}

$A将永远是Hello，因为它是在While范围之外 $B将永远改变，因为它在While范围内。（这也是因为每次您将$ B都替换为读取主机时调用）

您要做的是在ServerName上提供一个选项，并将变量放置在while范围之外。

$CurrentServer = $Null
$CurrentService = $Null
do {
    if(!($CurrentServer) -or $(Read-Host 'Change Server (Y,N)?') -eq "Y"){
        $CurrentServer = Read-Host 'What is your ServerName?'
    }

    if(!($CurrentService) -or $(Read-Host 'Change Service (Y,N)?') -eq "Y"){
        $CurrentService = Read-Host 'What is ServiceName?'
    }

    $userMenuChoice = Read-Host -Prompt @"
1. ServiceList
2. Service Status.
3. Stop Service.
4. Start Service.
5. Exit
Please Select Operation
"@
    switch($userMenuChoice){
        1{Get-Service -ComputerName $CurrentServer | select -property name,starttype}
        2{gsv -cn $CurrentServer -Name "$CurrentService*" | Out-String}
        3{Get-Service -Name "$CurrentService*" -ComputerName $CurrentServer | Stop-Service}
        4{Get-Service -Name "$CurrentService*" -ComputerName $CurrentServer | Start-Service}
        5{exit}
    }
} while ( $userMenuChoice -ne 4 )

行

if(!($CurrentServer) -or $(Read-Host 'Change Server (Y,N)?') -eq "Y"){}

允许您在需要时更改服务器和服务，但也可以在需要时跳过它。

这是说$CurrentServer是否为空，或者$CurrentServer的值为Ask Change Server，如果Change Server为Y，则运行if

Answer 2

这似乎太简单了。将Read-Host cmdlet放在循环外部。

$srv = Read-Host 'What is your ServerName?'
$srvs = Read-Host 'What is ServiceName?'

do {
  $userMenuChoice = Read-Host -Prompt "
  `n1. ServiceList
  `n2. Service Status.
  `n3. Stop Service.
  `n4. Start Service.
  `n5. Exit
  `nPlease Select Operation"
   switch($userMenuChoice){
     1{Get-Service -ComputerName $srv | select -property name,starttype}
     2{gsv -cn $srv -Name "$srvs*" | Out-String}
     3{Get-Service -Name "$srvs*" -ComputerName $srv | Stop-Service}
     4{Get-Service -Name "$srvs*" -ComputerName $srv | Start-Service}
     5{exit}
   }
 } while ( $userMenuChoice -ne 4 )

如何在Powershell菜单中创建菜单的见解

2 个答案: