Question

我有一个ListView，当您单击该项目时，它会打开一个包含许多详细信息的新页面，但是，如果单击“名称”（标题），它将显示一个包含该客户详细信息的弹出窗口。

我的问题是“名称/标题”单击不起作用。

public ICommand CommandShowInfo { get; set; }

public CustomerListViewModel(INavigation navigation, DateTime month)
    {
        _navigation = navigation;
        CommandShowInfo = new Command(ShowCustomerInfo);
        ....
    }


private async void ShowCustomerInfo(object obj)
        {
            if (obj.ToString() == "SHOW-MAIN")
            {
                CustInfoSelectedCustomer = MainCustomer;

                showDetails = true;
            }
            else if (obj.ToString() == "SHOW")
            {
                // TODO get correct customer to populate popup
                CustInfoSelectedCustomer = SelectedCustomer;

                showDetails = true;
            }
            else
            {
                showDetails = false;
            }
        }

<ListView ItemsSource="{Binding SummaryReports.ResultSet}" SelectedItem="{Binding SelectedCustomer}" HorizontalOptions="Fill">
	<ListView.ItemTemplate>
		<DataTemplate>
			<ViewCell>
				<ViewCell.View>
					<StackLayout Orientation="Vertical">
						<StackLayout Orientation="Horizontal" Padding="10,5,0,5" HorizontalOptions="Fill" Spacing="0">
							<StackLayout Orientation="Vertical" Padding="10,0,0,0" HorizontalOptions="FillAndExpand" Spacing="0">
								<StackLayout Orientation="Horizontal" Padding="0,0,0,5">
									<Label
                                        Text="{Binding Customer.Name}"
                                        LineBreakMode="TailTruncation"
                                        Font="{x:Static statics:Fonts.ListItemTitle}"
                                        TextColor="{x:Static statics:Palette.ListItemTitle}" />

                                                 <Image Source="info.png" Grid.Row="0" Grid.Column="2" HorizontalOptions="EndAndExpand" VerticalOptions="Center" WidthRequest="60" HeightRequest="20">
                                                    <Image.GestureRecognizers>
                                                        <TapGestureRecognizer
                                                            Command="{Binding CommandShowInfo}"
                                                            CommandParameter="SHOW" />
                                                    </Image.GestureRecognizers>
                                                </Image>

                                </StackLayout>
							</StackLayout>
							<StackLayout>
								....

Answer 1

我已经运行了您的代码，没有问题。您可以尝试

ALTER TABLE `stocktakings` MODIFY `stocktakings`.`status` ENUM(
            'ready_for_relocation',
            'search_shelf_location',
            'stock_update_succeeded',
            'stock_update_failed',
            'updating_stock'
    );

在模型中，您应该确保<Label Text="{Binding Name}" Style="{DynamicResource TitleStyle}"> <Label.GestureRecognizers> <TapGestureRecognizer Command="{Binding CommandShowInfo}" CommandParameter="Binding ." /> </Label.GestureRecognizers> </Label>必须位于 ListView.ItemSource 中，否则将无法正常工作。就像这样

CommandShowInfo

在contentapge中

 class Monkey
{
   public string Name { set; get; }
   public System.Windows.Input.ICommand CommandShowInfo { get; set; }
}

 class MonkeysViewModel
{
    public MonkeysViewModel()
    {

         private async void ShowCustomerInfo(object obj)
         {
             Console.WriteLine("true");
         }
        Monkeys = new List<Monkey>();
        //f = new F[5];
        Monkeys.Add(new Monkey
        {
            Name = "AS",
            CommandShowInfo = new Command(ShowCustomerInfo)
         });
     }
 }

在xaml中

 BindingContext = new MonkeysViewModel();

因此<ListView ItemsSource="{Binding Monkeys}"可以正常工作。

具有2个不同选择选项的Xamarin.Forms ListView

1 个答案: