Question

在我的视图中获取未定义的变量

WHERE b.salary > a.salary

//我的观点

public function confirm()
    {
        $data = Transaction::select('number','total','package')->where('user_id','=',\Auth::user_id()->id)->first();

       return view('user.package',compact('data'));

    }

Answer 1

从\Auth::user_id()->id更改为\Auth::user()->id

$data = Transaction::select('number','total','package')->where('user_id',\Auth::user()->id)->first();

通过两种方式获取当前的身份验证用户ID。

1.Auth::id();
2.Auth::user()->id

在您看来isset condition row is exist or not

            @isset($data)
                <center> 
                   <h3 class="card-title"><b>You are about to buy {{$data->number}} package of {{$data->package}} for {{$data->total}}</b>
                  </h3>
                </center>
             @endif

Answer 2

尝试使用-> get（）代替-> first（）

Answer 3

使用此

use Auth;
public function confirm()
{
    $data = Transaction::select('number','total','package')->where('user_id','=',Auth::user()->id)->first();

   return view('user.package',compact('data'));

}

Answer 4

尝试用auth()->user()->id代替\Auth::user_id()->id

或您可以使用

之类的口才关系

$user->with('Transaction')->select('number','total','package')->first();

在laravel视图5.7中获取未定义的变量

4 个答案: