Python：查看两个数组中的每个数字是否相同，最快/最优雅的方法是什么？

Question

即，比较：

1,-1,1 

到

1.0,-1, 1

应该是相同的

print("the input and the output are " + ( (input == calc_out) ? "the same" : "not the same"))

但它会出现词汇错误= \

Answer 1

==

Answer 2

文档指出various ways您可以比较序列和其他类型：

(1, 2, 3)              < (1, 2, 4)
[1, 2, 3]              < [1, 2, 4]
'ABC' < 'C' < 'Pascal' < 'Python'
(1, 2, 3, 4)           < (1, 2, 4)
(1, 2)                 < (1, 2, -1)
(1, 2, 3)             == (1.0, 2.0, 3.0)
(1, 2, ('aa', 'ab'))   < (1, 2, ('abc', 'a'), 4)

所以对你的例子来说：

C:\Users\jon>python
Python 2.6.5 (r265:79096, Mar 19 2010, 21:48:26) [MSC v.1500 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> [1,-1,1] == [1.0,-1,1]
True

Answer 3

发现它...... Python确实让Ternary很奇怪：

print("the input and the output are " + ( "the same" if (input == calc_out)  else "not the same"))